As per the details in the question the series is in the form of
Next term = Previous term × variable +variable
First term = 11
Second term = First term × 1.5 + 1.5
? Second term = 11 × 1.5 + 1.5 = 18 ;
Third term = Second term × 2 + 2
? Third term = 18 × 2 + 2 = 39 , is wrong . it should be 38 as third term .
Similarly , we can find all others terms also.
Fourth term = Third term × 2.5 + 2.5
? Fourth term = 38 × 2.5 + 2.5 = 97.5 ;
Fifth term = Fourth term × 3 + 3
? Fifth term = 97.5 × 3 + 3 = 295.5 ;
Sixth term = Fifth term × 3.5 + 3.5
? Sixth term = 295.5 × 3.5 + 3.5 = 1037.75 ;
New series is given as -
First term = 39 × 1.5 + 1.5 = 60;
Second term = 60 × 2 + 2 = 122.
Hence Second term of new series is 122.
As per the details in the question the series is in the form of
First term = 2
Second term = First term × 1 + 7
? Second term = 2 × 1 + 7 = 2 + 7 = 9 ;
Third term = Second term × 2 - 11
? Third term = 9 × 2 - 11 = 18 - 11 = 5; 5 is wrong. It should be 7 as Third term .
Similarly , we can find all others terms also.
Fourth term = Third term × 3 + 15
? Fourth term = 7 × 3 + 15 = 21 + 15 = 36 ;
Fifth term = Fourth term × 4 - 19
? Fifth term = 36 × 4 - 19 = 144 -19 = 125 ;
Sixth term = Fifth term × 5 + 23
? Sixth term = 125 × 5 + 23 = 625 + 23 = 648 ;
Seventh term = Sixth term × 6 - 27
? Seventh term = 648 × 6 - 27 = 3888 - 27 = 3861 .
New series is
First term = 5 × 1 + 7 = 12;
Second term = 12 × 2 - 11 = 13.
Hence Second term of new series is 13 and correct option is ( E ) .
The given series is in the below pattern,
First term = 2
Second term = ( First term × 2 ) + 3
? Second term = ( 2 × 2 ) + 3 = 7 ;
Third term = ( Second term × 2 ) + 5
? Third term = ( 7 × 2 ) + 5 = 19
Similarly , we can calculate all others terms also.
Fourth term = ( Third term × 2 ) + 7
? Fourth term = ( 19 × 2 ) + 7 = 43 , is wrong.it should be 45 as fourth term .
Fifth term = ( Fourth term × 2 ) + 9
? Fifth term = ( 45 × 2 ) + 9 = 99 ;
Sixth term = ( Fifth term × 2 ) + 11
? Sixth term = ( 99 × 2 ) + 11 = 209 ;
Seventh term = ( Sixth term × 2 ) + 11
? Seventh term = ( 209 × 2 ) + 13 = 431
New series is given as -
First term = 43 × 2 + 3 = 89;
Second term = 89 × 2 + 5 = 181.
Hence Second term of new series is 181.
From above given series , we can see that
Next term = Previous term × variable + variable2
First term = 1
Second term = First term × 1 + 12
? Second term = 1 × 1 + 12 = 1 + 1 = 2 ;
Third term = Second term × 2 + 22
? Third term = 2 × 2 + 22 = 4 + 4 = 6; 6 is wrong. It should be 8. Here, 6 is the wrong number.
Similarly , we can find all others terms also.
Fourth term = Third term × 3 + 32
? Fourth term = 8 × 3 + 32 = 24 + 9 = 33 ;
Fifth term = Fourth term × 4 + 42
? Fifth term = 33 × 4 + 42 = 132 + 16 = 148 ;
Sixth term = Fifth term × 5 + 52
? Sixth term = 148 × 5 + 52 = 740 + 25 = 765 ;
Seventh term = Sixth term × 6 + 62
? Seventh term = 765 × 6 + 62 = 4590 + 36 = 4626 .
New series is given as :-
First term = wrong term × 1 + 12 = 6 × 1 + 12 = 7;
Second term = wrong term × 1 + 12 = 6 × 2 + 22 = 16.
Hence Second term of new series is 16 .
From given figure , it is clear that
On adding 2 and subtracting 2 alternately in fourth term of given series .
We get , The next term of above given series is IRJQP .
From given figure , it is clear that
On adding 2 in Each letter of given series .We get , The next term of above given series is YXW.
Hence the correct option will be B .
The given series is in the below pattern,
1st letter moves +2, +3 and +4 steps respectively.
2nd letter moves ?2, ?3 and ?4 steps respectively.
Hence the place value of ? is JQ .
As per the details in the question the series is in the form of
The first letters of the terms are in alphabetical order, and so are the second and third letters.
Hence required answer will be SXI .
The first letters of the terms are consecutive letters. The third letter of each term is moved three steps backward to obtain the third letter of the successive term. The middle letters of the first, second, third and fourth terms are moved one, two, three, and four steps forward respectively to obtain the middle letter of the successive terms.
The order of above series given as - + 1 , + 2 , - 3
MHZ, NIW, OKT, PNQ, ( ? )
So ? = QRN ? 17 18 14
Hence , required answer will be QRN .
6 | 3.0 | 4.5 | 2.25 | 4.0 | 12 |
40 | (a) | (b) | (c) | (d) | (e) |
Which of the following numbers will come in place of (c)? |
The given series is in the below pattern ,
First series :-
First term = 6
Second term = First term ÷ 2
? Second term = 6 ÷ 2 = 3
Third term = Second term × 1.5
? Third term = 3 × 1.5 = 4.5
similarly , we can calculate the all next terms .
........... and so on.
Second series :-
First term = 40
Second term = First term ÷ 2
? Second term = 40 ÷ 2 = 20
Third term = Second term × 1.5
? Third term = 20 × 1.5 = 30
Fourth term = Third term ÷ 2
? Fourth term = 30 ÷ 2 = 15
Hence , the place value of (c) is 15 .
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