Mathematical Operations problems
- 1. Select the correct set of symbols which will fit in the given equation? 5 0 3 5 = 20
Options- A. x, x, x
- B. -, +, x
- C. x, +, x
- D. +, -, x Discuss
Correct Answer: -, +, x
Explanation:
Clearly 5 - 0 + 3 X 5 = 20
- 2. If × means ÷, - means ×, ÷ means + and + means- than (3 - 15 ÷ 19) × 8 + 6 = ?
Options- A. 8
- B. 4
- C. 2
- D. -1 Discuss
Correct Answer: 2
Explanation:
By the given data, we have the expression :
(3 × 15 + 19) ÷ 8 - 6 = (45 + 19) ÷ 8 - 6 = 64 ÷ 8 - 6 = 8 - 6 = 2
- 3. 12:30 :: 14: ?
Options- A. 36
- B. 28
- C. 35
- D. 42 Also asked in: Bank Exams, Bank Clerk
Correct Answer: 35
Explanation:
Here 12 x 2.5 = 30
In the same way 14 x 2.5 = 35
- 4. If Q means 'add to', J means 'multiply by', T means 'substract from' and K means 'divide by' then 30 K 2 Q 3 J 6 T 5 = ?
Options- A. 18
- B. 28
- C. 31
- D. 103 Discuss
Correct Answer: 28
Explanation:
Using Correct Symbols , We have :
Given expression = 30 / 2 + 3 x 6 - 5 = 15 + 18 - 5 = 28
- 5. In a group of buffaloes and ducks the number of legs are 24 more than twice the number of heads. What is the number of buffaloes in the group ?
Options- A. 6
- B. 18
- C. 12
- D. 24 Also asked in: CAT
Correct Answer: 12
Explanation:
Let the number of buffaloes be x
and number of ducks be y.
Now, number of heads = x+y
Number of legs = 4x+2y .......(1)
But given that legs = 2(x+y)+24 ......(2)
solving (1) & (2),we get
4x+2y=2x+2y+24
--> x=12.
Therefore number of buffaloes =12
- 6. In a cricket match, five batsmen P, Q, R, S and T scored an average of 36 runs. S Scored 5 more than T; T scored 8 fewer than P; Q scored as many as S and T combined; and Q and R scored 107 between them. How many runs did T score ?
Options- A. 20
- B. 29
- C. 28
- D. 24 Also asked in: AIEEE, Bank Exams, CAT, Bank Clerk, Bank PO
Correct Answer: 20
Explanation:
Let the runs scored by P, Q, R, S and T be a, b, c, d and e
From given data,
a + b + c + d + e = 36 x 5 = 180
b + c = 107
Let a = x
e = x-8
d = x-3
now 3x - 11 + 107 = 180
3x = 84
x = 28
e's score = 28-8 = 20
- 7. The solution of 3(2u + v) = 7 uv and 3(u + 3v) = 11 uv is _____
Options- A. u = 1, v = 0
- B. u = 1, v = 3/2
- C. u = 0, v = 3/4
- D. u = 0, v = 1 Also asked in: AIEEE, Bank Exams, CAT, Analyst, Bank Clerk, Bank PO
Correct Answer: u = 1, v = 3/2
Explanation:
Using Trial and error method,
From the options u = 1, v = 3/2 satisfies both the equations.
- 8. What approximate value will come in place of question mark (?) in the following question ? (49.001)2 = ?
Options- A. 2500
- B. 2400
- C. 2600
- D. 2300 Also asked in: AIEEE, Bank Exams, CAT, GATE, Bank Clerk, Bank PO
Correct Answer: 2400
Explanation:
Given (49.001)2 = ?
=> =~ 49 x 49
=~ 2401
=~ 2400
- 9. What should come in place of the question mark(?) in the following questions ? 316 + 412 - 223 - 11112 = ?
Options- A. 1 7/12
- B. 1 5/12
- C. 3 7/12
- D. 3 1/12 Also asked in: CAT, Bank Exams, AIEEE, Bank PO, Bank Clerk
Correct Answer: 3 1/12
Explanation:
? = (3 + 4 - 2 - 1) + ( 1/6 + 1/2 - 2/3 - 11/12)
= 4 + [(2+6-8-11)/12]
= 4 - (11/12 )= 31/12.
- 10. A sum of Rs.1890 has to be used to give 9 prizes to the customers of a super market for their overall academic purchases. If each prize is Rs.30 less than its preceding price, what is the least value of the price ?
Options- A. 90
- B. 95
- C. 85
- D. 80 Also asked in: CAT, Bank Exams, Bank PO, Bank Clerk
Correct Answer: 90
Explanation:
Let the least value of the prize = Rs. x
Then the next value of the prize is x+30 , x+60, x+90, ....x+240.
Given total amount of cash prizes = Rs.1890
--> x + (x+30) + (x+60) + (x+90) + ....+ (x+240) = 1890
--> 9x + (30 + 60 + 90 + 120 + 150 + 180 + 210 + 240) = 1890
--> 9x + 30(1 + 2 + 3 + 4....+ 8) = 1890
--> 9x + 30(36) = 1890
--> 9x = 810 --> x=90
Hence the least value of the prize x=90
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