Solve all option one by one,
36 + 6 - 3 x 2 = 20
After changing the symbol as per question,
36 ÷ 6 x 3 + 2 = 20
Apply the BODMAS rule,
? 6 x 3 + 2 = 20
? 18 + 2 = 20
? 20 = 20

Conclusions
As per given question, we can draw the below conclusion,
I. D > N           (?)
     
II. C ? K           (X)

Conclusion
I. C > N         (?)
II. B > N           (?)

K ? L > M ? N
Conclusions
I. N ? K             (x)
II. N < K            (?)
Thus, only Conclusion II follows.

Z ? Y = W ? X
Conclusions
I. W < Z          (?)
      or
II. W = Z             (?)
Thus, either Conclusion I or II follows.

Statements
R # J ? R >J
J $ D ? J ? D
D @ K ? D = K
K % T ? K ? T
i.e., R > J ? D = K ? T
Conclusions
I. T # D ? T > D       (may be)
II. T @ D ? T = D          (may be)
III. R # K ? R > K           (?)
IV. J $ T ? J ? T             (x)
Hence, either conclusion I or II and III are definitely true.

Statements
T % R ? T ? R
R $ M ? R ? M
M @ D ? M = D
D © H ? D < H
i.e., T ? R ? M = D < H
Conclusions
I. D % R ? D ? R         (?)
II. H # R ? H > R           (x)
III. T ©M ? T < M           (x)
IV. T % D ? T ? D          (x)

Hence conclusion I is definitely true.

Statements
M @ B ? M = B
B # N ? B > N
N $ R ? N ? R
R © K ? R < K
i.e., M = B > N ? R < K
Conclusions
I. K # B ? K > B          (x)
II. R © B ? R < B         (?)
III. M $ R ? M ? R        (x)
IV. N © M ? N < M      (?)
Hence, II and IV are definitely true.

Statements
F # H ? F > H
H @ M ? H = M
M © E ? M < E
E $ J ? E ? J
i.e., F > H = M < E ? J
Conclusions
I. J © M ? J < M           (x)
II. E # H ? E > H          (?)
III. M © F ? M < F        (?)
IV. F # E ? F > E            (x)
Hence, II and III are definitely true.

Statements ::
D % A ? D ? A
A @ B ? A = B
B © K ? B < K
K % M ? K ? M
i.e., D ? A = B < K ? M
Conclusions
I. B $ D ? B ? D         (?)
II. K # A ? K > A         (?)
III. M # B ? M > B         (?)
IV. A © M ? A < M         (?)
Hence, all Conclusion I, II, III and IV are definitely true.