Draw a figure.
Rohan walks a distance of 3 km towards North.
Then turns to his left and walks for 2 km.
He again turns left and walks for 3 km.
At this point he turns to his left and walks for 3 km.
The movements of Maya from T to R are as shown in Figure.
Distance between T and R = TR = TU + UR = TU + PW + QV = ( 4 + 3 + 1) ft = 8 ft.
The movements of Sanjeev from A to F are as shown in Figure Clearly,
Sanjeev's distance from starting point A
= AF = (AB + BF) = AB + ( BE ? EF ) = AB + (CD ? EF)
= [10 + (20 ? 10)] m = (10 + 10) m = 20 m.
Also, F lies to the South of A. So, Sanjeev is 20 meters to the south of his starting point.
Drawing a figure for the movement of a man as below.
Draw a figure for 1 km towards East.
Then Draw another figure for 5 km in south.
Again draw a line when he turns to East and walks 2 km,
after this draw a line when he turns to North and walks 9 km.
The movements of A are as shown in Figure (O to P, P to Q, Q to R, R to S and S to T)
Since TS = OP + QR, so T lies in line with O. A's distance from the starting point O = OT = (RS ? PQ) = (15 ? 10)m = 5 m.
The movements of the man from A to F are as shown in Figure Clearly,
DC = AB + EF
Therefore, F is in line with A
Also, AF = (BC ? DE) = 5 m.
So, the man is 5 meters away from his initial position.
It is clear from the diagram that Kamu is to the west of her house.
Hence required answer will be west direction.
From given diagram , It is clear that Janaki is going towards south.So Answer will be south direction .
It is clear from the diagram that Mohan is facing towards North.
Now Suresh is in the East direction from the starting point.
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