Since, in one hour, two hands of a clock coincide only once, so, there will be value.
Required time
minutes past H.
Here H - initial position of hour hand = 2 (since 2 O'clock)
A° = Required angle = 0° (Since it coincides)
minutes past 2
=> minutes past 2
Apply the formula for finding the angle:
Angle=(30h-(11/2)m( where m stands for minutes and h stands for hours)
Hence, 30x11 - 11/2x35 = 330 - 192.5 = 137.5 degrees
The reflex angle = 360 - 192.5 degree = 222.5 degrees.
The total angle traced by the hour hand is the angle traced in 7 hours and 10 minutes.
We know that the angle traced by the hour hand in one hour is 30º and in one minute is 1/2º.
Therefore, (30º x 7) + (10 x 1/2º) = 215º is the angle traced by the hour hand.
For 1 hour, 20 minutes is slower, then for
06 miuntes - 2 minutes is slower
30 minutes - 10 minutes
Actual time | false time
12 12
01 PM 12:40 PM (20 minutes slower)
02 PM 01:20 PM
03 PM 02:00 PM
So, when actual time is 3pm, the false time is 2 pm.
So, it loses 60 minutes when it shows 2 pm.
Let the required number of minutes = M
Total minutes between 3o'clock and 6o' clock = 180 minutes
M + 50 + 4M = 180
5M + 50 = 180
5M = 130
M = 26 minutes.
There are 60 minutes in an hour.
In ¾ of an hour there are (60 × ¾) minutes = 45 minutes.
In ¾ of an hour there are (60 × 45) seconds = 2700 seconds.
Siren sounds for every 5 seconds.
In 2700 seconds = 2700/5 = 540 times.
The count start after the first sound, the Siren will sound 541 times in ¾ of an hour.
Copyright ©CuriousTab. All rights reserved.