Given principal amount = Rs. 8000
Time = 3yrs
Rate = 5%
C.I for 3 yrs =
Now, C.I for 2 yrs =
Hence, the required difference in C.I is 1261 - 820 = Rs. 441
We know that,
From given data, P = Rs. 8625
Now, C.I =
C.I =
594.5 =
% .
> 2P
Now, (6/5 x 6/5 x 6/5 x 6/5) > 2.
So, n = 4 years.
P = Rs. 15225, n = 9 months = 3 quarters, R = 16% p.a. per quarter.
Amount =
= (15225 x 26/25 x 26/25 x 26/25) = Rs. 17126.05
=> C.I. = 17126 - 15625 = Rs. 1901.05.
Given,
Compound rate, R = 10% per annum
Time = 2 years
C.I = Rs. 420
Let P be the required principal.
A = (P+C.I)
Amount, A =
(P+C.I) =
(P+420) = P[11/10][11/10]
P-1.21P = -420
0.21P = 420
Hence, P = 420/0.21 = Rs. 2000
Amount =
= 8000 x 21/20 x 21/20
= Rs. 8820
Let p = Rs. 100.
Then, S.I is Rs. 50 and time = 5 years.
= 10% p.a.
Now, p = Rs. 12,000 , T = 3 years and R = 10% p.a.
C.I. = Rs.
= Rs. 3972
Rs.1440 - 1200 = Rs.240 is the interest on Rs.1200 for one year.
Rate of interest = (100 x 240) / (1200) = 20% p.a
Let the sum be Rs.x. Then,
=> x =5500
sum = Rs. 5500.
So, S.I = Rs. = 1100
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