Chain Rule problems
- 1. If a quarter kg of carrots costs 60 paise, how many paise will 200 gms cost ?
Options- A. 78 paise
- B. 48 paise
- C. 54 paise
- D. 62 paise Also asked in: AIEEE, Bank Exams, CAT, GATE, Bank Clerk, Bank PO
Correct Answer: 48 paise
Explanation:
Quarter of Kg means 250 gm
Less weight, less price (Direct Proportion)
So,
250 : 200 :: 60 : x => x = 48
So 200 gm will cost 48 paise.
- 2. The sum of 3rd and 15th elements of an arithmetic progression is equal to the sum of 6th, 11th and 13th elements of the same progression. Then which element of the series should necessarily be equal to zero ?
Options- A. 14th element
- B. 9th element
- C. 12th element
- D. 7th element Also asked in: AIEEE, Bank Exams, CAT, GATE, Bank Clerk, Bank PO
Correct Answer: 12th element
Explanation:
If we consider the third term to be ?x?
The 15th term will be (x + 12d)
6th term will be (x + 3d)
11th term will be (x + 8d) and
13th term will be (x + 10d).
Thus, as per the given condition, 2x + 12d = 3x + 21d.Or x + 9d = 0.
x + 9d will be the 12th term.
Thus, 12th term of the A.P will be zero.
- 3. In a queue, Shankar is ninth from the rear end. Althaf's place is eighth from the front. Nitu is standing between the two. What could be the minimum numbers of boys standing in the queue ?
Options- A. 18
- B. 14
- C. 22
- D. 24 Also asked in: AIEEE, Bank Exams, CAT, GATE, GRE, Bank Clerk, Bank PO
Correct Answer: 14
Explanation:
1 2 3 4 5 6(Shankar) 7(Nitu) 8(Althaf) 9 10 11 12 13 14
Here, Althaf is 8th from front, Shankar is 9th from rear end and Nitu is between them
So minimum no. of boys standing in the queue = 14
- 4. If a person having Rs. 2000 and he want to distribute this to his five children in the manner that each son having Rs. 30 more than the younger one , what will be the share of youngest child ?
Options- A. Rs. 175
- B. Rs. 325
- C. Rs. 340
- D. Rs. 260 Also asked in: AIEEE, Bank Exams, CAT, GATE, GRE, Analyst, Bank Clerk, Bank PO
Correct Answer: Rs. 340
Explanation:
Assume first child (the youngest) get = Rs. x
According to the question ;
each son having Rs. 30 more than the younger one
Second child will get = Rs. x + 30
Third child will get = Rs. x + 30 + 30 = x + 60
Forth child will get = Rs. x + 30 + 30 + 30 = x + 90
Fifth child will get = Rs. x + 30 + 30 + 30 + 30 = x + 120
Total amount they got = Rs. 2000
x + (x+30) + (x+60) + (x+90) + (x+120) = 2000
5x + 300 = 2000
5x = 1700
x = Rs. 340
So the youngest child will get Rs. 340.
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