Area problems
- 1. Find the length of a rope by which a cow must be tethered in order that it may be able to graze an area of 9856 sq meters.
Options- A. 56m
- B. 16m
- C. 14m
- D. 76m Also asked in: Bank Exams, Bank PO
Correct Answer: 56m
Explanation:
clearly the cow will graze a circular field of area 9856 sq m and radius equal to the length of the rope.
Let the length of the rope be r mts
then,
- 2. Square units 13 by 9 of an office area is
Options- A. 97
- B. 117
- C. 107
- D. 127 Also asked in: AIEEE, Bank Exams, CAT, GATE, Analyst, Bank Clerk, Bank PO
Correct Answer: 117
Explanation:
Square units 13 by 9 of an office means office of length 13 units and breadth 9 units.
Now its area is 13x 9 = 117 square units or units square.
- 3. Find the area of the trapezium, whose parallel sides are 12 cm and 10 cm, and distance between the parallel sides is 14 cm?
Options- A. 121 sq.com
- B. 154 sq.com
- C. 186 sq.com
- D. 164 sq.com Also asked in: AIEEE, Bank Exams, CAT, Analyst, Bank Clerk, Bank PO
Correct Answer: 154 sq.com
Explanation:
We know that,
Area of trapezium = 1/2 x (Sum of parallel sides) x (Distance between Parallel sides)
= 1/2 x (12 + 10) x 14
= 22 x 14/2
= 22 x 7
= 154 sq. cm
- 4. The area of the circle is 220 sq.m, the area of the square inscribed in a circle will be
Options- A. 49
- B. 70
- C. 140
- D. 150 Also asked in: Bank Exams, Bank PO
Correct Answer: 140
Explanation:
area of a square =
- 5. The sides of a right-angled triangle are 12 cm, 16 cm, 20 cm respectively. A new right angle Δ is made by joining the midpoints of all the sides. This process continues for infinite then calculate the sum of the areas of all the triangles so made.
Options- A. 312 sq.cm
- B. 128 sq.cm
- C. 412 sq.cm
- D. 246 sq.cm Also asked in: AIEEE, Bank Exams, CAT, Analyst, Bank Clerk, Bank PO
Correct Answer: 128 sq.cm
- 6. The difference between two parallel sides of a trapezium is 4 cm. perpendicular distance between them is 19 cm. If the area of the trapezium is 475 find the lengths of the parallel sides.
Options- A. 27 and 23
- B. 24 and 23
- C. 25 and 23
- D. 22 and 23 Also asked in: Bank Exams, Bank PO
Correct Answer: 27 and 23
Explanation:
Let the two parallel sides of the trapezium be a cm and b cm.
Then, a - b = 4
And,
Solving (i) and (ii), we get: a = 27, b = 23.
So, the two parallel sides are 27 cm and 23 cm.
- 7. The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ Rs. 26.50 per metre is Rs. 5300, what is the length of the plot in metres?
Options- A. 20
- B. 200
- C. 300
- D. 400 Also asked in: Bank Exams, Bank PO
Correct Answer: 200
Explanation:
Let length of plot = L meters, then breadth = L - 20 meters
and perimeter = 2[L + L - 20] = [4L - 40] meters
[4L - 40] * 26.50 = 5300
[4L - 40] = 5300 / 26.50 = 200
4L = 240
L = 240/4= 60 meters.
- 8. A room is 15 feet long and 12 feet broad. A mat has to be placed on the floor of the room leaving 1.5 feet space from the walls. What will be the cost of the mat at the rate of Rs. 3.50 per squire feet?
Options- A. 378
- B. 472.5
- C. 496
- D. 630 Also asked in: Bank Exams, Bank PO
Correct Answer: 378
- 9. The perimeter of a rectangle whose length is 6 m more than its breadth is 84 m. What will be the area of the rectangle?
Options- A. 333 sq.mts
- B. 330 sq.mts
- C. 362 sq.mts
- D. 432 sq.mts Also asked in: AIEEE, Bank Exams, CAT, GATE, Analyst, Bank Clerk, Bank PO
Correct Answer: 432 sq.mts
Explanation:
Let the breadth of the rectangle = b mts
Then Length of the rectangle = b + 6 mts
Given perimeter = 84 mts
2(L + B) = 84 mts
2(b+6 + b) = 84
2(2b + 6) = 84
4b + 12 = 84
4b = 84 - 12
4b = 72
b = 18 mts
=> Length = b + 6 = 18 + 6 = 24 mts
Now, required Area of the rectangle = L x B = 24 x 18 = 432 sq. mts
- 10. What is the least number of squares tiles required to pave the floor of a room 15.17 m long and 9.02 m broad?
Options- A. 814
- B. 714
- C. 614
- D. 713 Also asked in: Bank Exams, Bank PO
Correct Answer: 814
Explanation:
Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm.
Area of each tile =
Required number of tiles = = 814
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