Area problems
- 1. A rectangular plot measuring 90 metres by 50 metres is to be enclosed by wire fencing. If the poles of the fence are kept 5 metres apart, how many poles will be needed?
Options- A. 56m
- B. 65m
- C. 34m
- D. 36m Also asked in: Bank Exams, Bank PO
Correct Answer: 56m
Explanation:
Length of the wire fencing = perimeter = 2(90 + 50) = 280 metres
Two poles will be kept 5 metres apart. Also remember that the poles will be placed along the perimeter of the rectangular plot, not in a single straight line which is very important.
Hence number of poles required = 280 / 5 = 56
- 2. The length and the breadth of rectangular field are in the ratio of 8 : 7. If charges of the painting the boundary of rectangle is at Rs. 10 per meter is Rs. 3000. What is the area of rectangular plot?
Options- A. 5600 sq.m
- B. 1400 sq. m
- C. 4400 sq.m
- D. 3600 sq.m Also asked in: AIEEE, Bank Exams, CAT, GATE, Analyst, Bank Clerk, Bank PO
Correct Answer: 5600 sq.m
Explanation:
Perimeter of the rectangle is given by 3000/10 = 300 mts
But we know,
The Perimeter of the rectangle = 2(l + b)
Now,
2(8x + 7x) = 300
30x = 300
x = 10
Required, Area of rectangle = 8x x 7x = 56 x 100 = 5600 sq. mts.
- 3. If the length of a certain rectangle is decreased by 4 cm and the width is increased by 3 cm, a square with the same area as the original rectangle would result. Find the perimeter of the original rectangle.
Options- A. 20
- B. 30
- C. 40
- D. 50 Also asked in: Bank Exams, Bank PO
Correct Answer: 50
Explanation:
Let x and y be the length and breadth of the rectangle respectively.
Then, x - 4 = y + 3 or x - y = 7 ----(i)
Area of the rectangle =xy; Area of the square = (x - 4) (y + 3)
(x - 4) (y + 3) =xy <=> 3x - 4y = 12 ----(ii)
Solving (i) and (ii), we get x = 16 and y = 9.
Perimeter of the rectangle = 2 (x + y) = [2 (16 + 9)] cm = 50 cm.
- 4. The no of revolutions a wheel of diameter 40cm makes in traveling a distance of 176m is
Options- A. 240
- B. 140
- C. 40
- D. 340 Also asked in: Bank Exams, Bank PO
Correct Answer: 140
Explanation:
distance covered in 1 revolution =
= 2 x (22/7) x 20 = 880/7 cm
required no of revolutions = 17600 x (7/880) = 140
- 5. A wheel makes 1000 revolutions in covering a distance of 88 km. Find the radius of the wheel.
Options- A. 14
- B. 13
- C. 12
- D. 11 Also asked in: Bank Exams, Bank PO
Correct Answer: 14
Explanation:
Distance covered in one revolution = = 88m.
- 6. A circular swimming pool is surrounded by a concrete wall 4ft wide. If the area of the concrete wall surrounding the pool is 11/25 that of the pool, then the radius of the pool is?
Options- A. 10ft
- B. 20ft
- C. 30ft
- D. 40ft Also asked in: Bank Exams, Bank PO
Correct Answer: 20ft
Explanation:
let the radius of the pool be Rft
Radius of the pool including the wall = (R+4)ft
Area of the concrete wall = = sq feet
=> 8
Radius of the pool R = 20ft
- 7. The breadth of a rectangular field is 60% of its length. If the perimeter of the field is 800 m.What is the area of the field?
Options- A. 47500
- B. 37500
- C. 57500
- D. 77500 Also asked in: Bank Exams, Bank PO
Correct Answer: 37500
Explanation:
Let length = x meters, then breadth = 0.6x
Given that perimeter = 800 meters
=> 2[ x + 0.6x] = 800
=> x = 250 m
Length = 250m and breadth = 0.6 x 250 = 150m
Area = 250 x 150 = 37500 sq.m
- 8. A typist uses a sheet measuring 20cm by 30cm lengthwise.If a margin of 2 cm is left on each side and a 3 cm margin on top and bottom, then percent of the page used for typing is
Options- A. 64%
- B. 74%
- C. 84%
- D. 94% Also asked in: Bank Exams, Bank PO
Correct Answer: 64%
Explanation:
Area of the sheet =
Area used for typing =
required % = =64%
- 9. The difference between circumference and semidiameter of a circle is 37 cm. What is the diameter of the circle ?
Options- A. 18 cm
- B. 12 cm
- C. 16 cm
- D. 14 cm Also asked in: Bank Exams, AIEEE, Bank PO, Bank Clerk, GATE, CAT
Correct Answer: 14 cm
Explanation:
circumference of a circle = 2 r
=> 2 × 22/7 × r ? r = 37
=> 37/7 × r = 37
=> r = 7 cm.
Diameter D = 2r = 7×2 = 14 cm.
- 10. If the sides of a triangle are 26 cm, 24 cm and 10 cm, what is its area ?
Options- A. 108 sq.cm
- B. 112 sq.cm
- C. 116 sq.cm
- D. 120 sq.cm Also asked in: AIEEE, Bank Exams, CAT, GATE, Bank Clerk, Bank PO
Correct Answer: 120 sq.cm
Explanation:
The triangle with sides 26 cm, 24 cm and 10 cm is right angled, where the hypotenuse is 26 cm.
Area of the triangle =1/2 x base x height => 1/2 x 24 x 10 = 120 sq.cm
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