Curved surface area = 2?r2
= 2? x 14 x 14 = 2 x (22/7) x 14 x 14
= 2 x 22 x 2 x 14
= 88 x 14
= 1232 sq cm
Given,
Diameter = 2 cm
? r = 1 cm
Now, Total surface area of hemisphere = 3?r2
and curved surface area = 2?r2
Required difference = 3?r2 - 2?r2 = ?r2
= ? x 12 = ? sq cm
Let radius of the third sphere be r.
Then, 4/3 ? x (12)3 = 4/3 ? x (6)3 + 4/3? x (8)3 + 4/3 ?r3
? (12)3 = (6)3 + (8)3 + r3
? r3 = 1728 - 216 - 512
? r3 = 1000
? r = 10 cm
According to the formula
Percentage increase in surface area = [ 2x + x2/100]%
= [2 x 3 + (3)2/100]%
= [6 + 0.09]%
= 6.09%
According to the formula,
Percentage decrease in surface area = [2 x (-24) + (-24) x (-24)/100]%
= [-48 + 5.76]% = - 42.24%
Here, n = 100%
According to the formula
Percentage increase in volume = [(1 + n/100)3 - 1] x 100%
= [(1 + 100/100)3 - 1] x 100%
= [8 - 1] x 100% = 700%
Volume of solid sphere of radius 4 cm = (4/3)?(4)3 cm3
Volume of hollow sphere = 4/3?[(8)3 - (6)3] cm3
? Weight of 4/3?(4)3 cm3 = 4 kg
= 4(512 - 216)/43 = 18.5 kg
Volume of prism = Area of base x Height
= (1/2) x 10 x 12 x 20
= 1200 cm2
? Weight of prism = 1200 x 6
= 7200 g
= 7.2 kg
Let the sides of the base are 5k, 12k and 13k, respectively.
Given, perimeter of base = 60 cm
? 5k + 12k + 13k = 60
? k = 60/30 = 2
The sides of base are 10 cm, 24 cm 26 cm.
? Volume of prism = (1/2) x 10 x 24 x 50 = 6000 cm3
Volume of the prism = (Area of the base ) x (Height)
Volume of the pyramid = 1/3 (Area of the base ) x (Height)
Required ratio = [A x H] / [(1/3) x A x H]
Therefore, Ratio of the volumes of the prism and the pyramid = 3 : 1.
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