Given that, R = 7%, T = 2 yr,
TD = ? 672 and Sum due (A) = ?
According to the formula, (3)
TD = (A x R x T) / (100 + R x T)
? 672 = (A x 7 x 2) / (100 + 7 x 2) = 14A/114
? A = (114 x 672)/14 = ? 5472
Given that, SI = ? 225, TD = ? 75,
T = 4 yr and R = ?
According to the formula,
SI - TD = (TD x R x T)/100
? 225 - 75 = (75 x R x 4)/100
? 150 = (75 x R x 4) /100
? 3R = 150
R = 50%
SP = 102% of ? 600 = (102/100) x 600 = ? 612
Now, PW = ? 612 and sum = ? 688.50
? TD = 688.50 - 612 = ? 76.50
Thus, SI on ? 612 for 9 months is ? 76.50.
? Rate = (100 x 76.50) / (612 x 3/4)
= (100 x 76.50) / (153 x 3)
=162/3%
Required sum = P.W. of Rs. 702 due 6 months + P.W. of Rs. 702 due 1 year hence.
= Rs. {100 x 702} / {100 + 8 x (1/2)} + Rs. {100 x 702} / {100 + 8 x 1}
? Total P.W. = Rs. (675 + 650)
= Rs. 1325
Time = 41/2 months = 3/8 year,
Rate = 4 percent
? Amount of Rs. 100 = 203/2
? P.W. = Rs. 456.75 / (203/2) x 100 = Rs. 450
Again, time = 3 months = 1/4 year, rate = 4 percent
P.W. = Rs. 455.51 x 100 x 101 = Rs. 451
Hence the required sum to be paid to A = Rs. 451 - Rs. 450 = Re. 1
PW of ? 6440 due 8 month hence
= (6440 x 100)/[100 + (18 x 8)/12] = (6440 x 100)/112 = ?5750
clearly, ? 10000 in cash is better offer.
Required cash = PW of ? 5014 due 9 month hence
= {95014 x 1000} /{100 + 12 x (9/12)}
= (5014 x 100)/(100 + 9)
= (5014 x 100)/109
= ? 4600
Money to be paid by Aarti
= PW of ? 440 due 1 yr hence
= {440 x 100}/{100 + (10 x 1)} = {440 x 100}/110
= 4 x 100 = ? 400
Aarti actually pays ? 220 + PW of ? 220 due yr hence
i.e. 220 + {(220 x 100) / (100 + 10 x 2)}
= 220 + (220 x 100)/120
= [220 + 183.33]
= ? 403.33
? Loss of Aarti = 403.33 - 400
= ? 3.33
N owes PW of ? 3146 due 3/2 yr hence
i.e. {3146 x 100} / {100 + (14 x 3/2)} = (3146 x 100) / (100 + 21)
= 314600 / 121
= ? 2600
N owes PW of ? 2889 due 6 months hence
i.e. {2889 x 100}/{100 + (14 x 1/2)} = (2889 x 100)/(100 + 7)
= (2889 x 100)/107 = ? 2700
? N must pay ? (2700 - 2600) i.e. ? 100 to M.
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