S.I on Rs. (110 - 10) for a given time = Rs. 10
S.I. on Rs. 100 for double the time = Rs. 20
Sum = Rs. (100 + 20) = Rs. 120
T.D. on Rs. 110 = Rs. (20/120) x 110 = Rs. 18.33
? P.W. = 39.69 / (1 + 5 / 100)2
= (3969 x 100 x 100) / (100 x 105 x 105) = Rs. 36
? True discount = Rs. 39.69 - 36 = Rs. 3.69
Here sum is put on compound interest,
? P.W. = A / (1 + r / 100)n = 2420 / (1 + 10 / 100)2 = 2420 x 100 / 121 = Rs. 2000
? T.D. = P.W. - P
? True discount = 2420 - 2000 = Rs. 420
? 5 = {(3050 - 3000) / (3000 x T)} x 100
? T = 1/3 years = 4 months
SI on rupees 100 for 10 months at 6% per annum = (100 x 10 x 6)/(12 x 100) = Rs. 5.
? Amount = 100 + 5 = 105.
So true discount = 105 - 100 = Rs. 5
So If TD = 5 then sum due = 100
So, when TD = 26.25 the sum = (100 x 26.25) / 5 = Rs. 551.25
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