Time and Distance problems
- 1. A man covered a distance of 12 km in 90 min by cycle. How much distance will he cover in 3 h, if he rides the cycle at a uniform speed?
Options- A. 36 km
- B. 24 km
- C. 30 km
- D. 27 km Discuss
Correct Answer: 24 km
Explanation:
We know that, speed = Distance / Time
Speed = 12/90 km/min
? Distance covered in 3 h = Speed x Time
= (12/90) x (3 x 60) = 24km
- 2. Two trains A and B travel from points X to Y and the ratio of the speeds of A to that of B is 2 : 7. Find the ratio of time taken by A and B to reach From X to Y.
Options- A. 2 : 5
- B. 3 : 5
- C. 3 : 8
- D. 7 : 2 Discuss
Correct Answer: 7 : 2
Explanation:
We know that speed is inversely proportional to time.
Given that, (Speed of A ) : (speed of B ) = 2 : 7
?(Time taken by A ) : (Time taken by B ) = 1/2 : 1/7 = 7 : 2
- 3. A man completes 30 km of a journey at 6 km/h and the remaining 40 km of the journey in 5 h. Find the average speed for the whole journey.
Options- A. 64/11 km/h
- B. 7 km/h
- C. 71/2
- D. 8 km/h Discuss
Correct Answer: 7 km/h
Explanation:
Total distance = 30 + 40 = 70 km
Total time taken = (30/6) + 5 = 10 h
? Required average speed = 70/10 = 7 km/h
- 4. A certain distance is covered at a certain speed. If half of the distance is covered in double time, the ratio of the two speeds is .
Options- A. 4 : 1
- B. 1 : 4
- C. 1 : 2
- D. 2 : 1 Discuss
Correct Answer: 4 : 1
Explanation:
Let L km distance be covered in T h. So, speed in first case = L/T km/h.
And speed in second case = (L/2)/2T = L/4T km/h
? Required ratio = L/T : L/4T =1 : 1/4 = 4 : 1
- 5. Moving 6/7 of its usual speed a train is 10 min late. Find its usual time to cover the journey.
Options- A. 25 min
- B. 15 min
- C. 35 min
- D. 60 min Discuss
Correct Answer: 60 min
Explanation:
New speed = 6/7 of usual speed
Now, time taken = 7/6 of usual time
(7/6 of the usual time) - (usual time) = 10 min
? 1/6 of the usual time = 10 min
? Usual time = 60 min
- 6. John started from A to B and Vinod from B to A. If the distance betweeen A and B is 125 km and they meet at 75 km from A, what is the ratio of John's speed to that of Vinod's speed?
Options- A. 2 : 3
- B. 3 : 2
- C. 4 : 3
- D. 5 : 4 Discuss
Correct Answer: 3 : 2
Explanation:
John's speed : Vinod's speed = 75 : ( 125 - 75 )
= 75 : 50 = 3 : 2
- 7. A person goes from one point to another point with a speed of 5 km/h and comes back to starting point with a speed of 3 km/h. Find the average speed for the whole journey.?
Options- A. 4.5 km/h
- B. 4 km/h
- C. 4. 25 km/h
- D. 3. 75 km/h Discuss
Correct Answer: 3. 75 km/h
Explanation:
Average speed = 2AB/(A + B)
= 2 x 5 x 3/(5 + 3)
= 30/8
= 3.75 km/h
- 8. A train covers a distance in 1 h 40 min, if it runs at a speed of 96 km/h on an average. Find the speed at which the train must run reduce the time of journey to 1 h 20 min.
Options- A. 120 km/h
- B. 90 km/h
- C. 144 km/h
- D. 150 km/h Discuss
Correct Answer: 120 km/h
Explanation:
Distance= Speed x Time = 96 x (100/60) = 160 km
New time = 80/60 h = 4/3 h
New speed = 160 x 3/4 = 40 x 3 =120 km/h
- 9. The average speed of a car is 75 km/h. The driver first decrease its average speed by 40% and then increase it by 50%. What is the new average speed now?
Options- A. 67.5 km
- B. 60 km
- C. 90 km
- D. 60.5 km Discuss
Correct Answer: 67.5 km
Explanation:
Required average speed = 75 x {(100 - 40)/100} x {(100 + 50)/100}
= 75 x 3/5 x 3/2
= 67.5 km/h
- 10. If a train runs at 5/6 of its original speed, then it reaches the station 10 min late. Then find out the usual time taken by train to cover the distance.
Options- A. 40 min
- B. 45 min
- C. 50 min
- D. 55 min Discuss
Correct Answer: 50 min
Explanation:
Let the actual speed of train be x and actual time taken be y
Then new speed of train = 5x/6
Therefore, new time taken = 6y/5 (as distance is same in both case)
Given, 6y/5 - y = 1/6 hr , therefore actual time = 50 min
More in Aptitude:
Programming
Copyright ©CuriousTab. All rights reserved.