Total running distance in four weeks = (24 x 240) + (4 x 400)

= 5760 + 1600

= 7360 meters

= 7360/1000

=> 7.36 kms

The first train covers 180 kms in 5 hrs

=> Speed = 180/5 = 36 kmph

Now the second train covers the same distance in 1 hour less than the first train => 4 hrs

=> Speed of the second train = 180/4 = 45 kmph

Now, required difference in distance in 1 hour = 45 - 36 = 9 kms.

Let the speed of goods truck be 'p' kmph
Distance covered by goods truck in 10hrs (4+6) = Distance covered by other truck in 4 hrs.
10p = 4 x 90
p = 36kmph.
Therefore, the speed of the goods truck is p = 36 kmph.

|-----------20--------------------|
50                           40

Difference = 20kms

Relative Speed = 50 ? 40 = 10 kmph

Time = 20/10 = 2 hours.

Let the distance between A and B = D

Given the speed of maruthi = 60 kmph

Maruthi reaches from A to B in 6 hrs 20 min = 6 + 20/60 = 6 1/3 hrs

Now, the distance between A & B = D = speed x time = 60 x 19/3 = 380 kms

As the distance is same for toyato also,

given time for toyato = 4 hrs 45 min = 4 + 45/60 = 4 3/4 = 19/4 hrs

speed of toyato = distance/time = 380/19/4 = 380 x 4/19 = 80 kmph.

A:B = 200 : 169
A:C = 200 : 182
  C B = C A × A B 

182 200 × 200 169

=> 182:169

When C covers 182 m , B Covers 169 m
When C covers 350 m , B Covers  169 182 × 350
=> 325 m

So C beats B by (350 - 325) = 25 m.

Relative Speed = 5 ¾ - 4 ½ = 1 ¼

Time = 3 ½ h.

Distance = 5/4 x 7/2 = 35/8 = 4 3/8 km.

Distance travelled by Ramu = 45 x 4 = 180 km

Somu travelled the same distance in 6 hours.

His speed = 180/6 = 30 km/hr

Hence in the conditional case, Ramu's speed = 45 - 9 = 36 km/hr and Somu's speed = 30 + 10 = 40km/hr.

Therefore travel time of Ramu and Somu would be 5 hours and 4.5 hours respectively.

Hence difference in the time taken = 0.5 hours = 30 minutes.

We know that

Time = Distance/speed
Required time = (10 1/4)/2 + (10 1/4)/6
= 41/8 + 41/6
= 287/24 = 11.9 hours.

60(x + 1) = 64x

X = 15

60 x 16 = 960 km