Note:
Here, original rate is for 1 year(s); the new rate is for only 4 months i.e. ⅓ year(s).
∴ | ❨ | 725 x R x 1 | ❩ | + | ❨ | 362.50 x 2R x 1 | ❩ | = 33.50 |
100 | 100 x 3 |
⟹ (2175 + 725) R = 33.50 x 100 x 3
⟹ (2175 + 725) R = 10050
⟹ (2900)R = 10050
⟹ R = | 10050 | = 3.46 |
2900 |
∴ Original rate = 3.46%
Since the principal is not given, so data is inadequate.
Gain in 2 years |
|
||||||||||||||||
= Rs. (625 - 400) | |||||||||||||||||
= Rs. 225. |
∴ Gain in 1 year = Rs. | ❨ | 225 | ❩ | = Rs. 112.50 |
2 |
∴ Required ratio = |
|
= | 6PR | = | 6 | = 2 : 3. | ||||
|
9PR | 9 |
Total interest needed in a year = Rs 400 × 12
= Rs 4800
Principal = (100 × SI)/R × T
where, R = Rate
T = Time
SI= Simple Interest
Here , P= Rs 1000
T= 4 yrs
R= 4 %
where, P= Principal
T= Time
R= Rate
Since , Simple Interest on Rs 1000=(1000 × 4 × 4)/100
= Rs 160
now, simple interest=Rs 160
P = Rs 400
R = 10 %
then, T=(100 × SI)/P × R
= (100 × 160)/(400 × 10)
= 4 yr
Let Sum = P, Then SI=P
As Amount A = 2 × P
where , P = Principal
Rate R = (100 × SI)/(P × T)
= (100 × P)/(P × 8) %
= 12.5 %
where , SI= Simple Interest
T= Time
Let the amount instalment be Rs ' x '
Then According to question,
(Amount of 'x' for 3 yrs) + (Amount of 'x' for 2 yrs) + (Amount of 'x' for 1 yrs) + x =3220
or, [x+(x × 10 × 3)/100] + [x+(x × 10 × 2)/100] + [x+(x × 10 × 1)/100] + x=3220
? 4x+ (30x/100)+(20x/100)+(10x/100)=3220
? 460x=322000
? x=Rs 700
? Each Instalment= Rs 700
Simple Interest in 1 year= Rs (1729 - 1586)
= Rs 143
now, SI in 2 year = Rs 286
Principal P= Rs(1586 - 286)
= 1300
And R= (100 × SI)/(P × T)
= (100 × 143)/(1300 × 1)
= 11 %
where, R = rate
SI= Simple Interest
P = Principal
T= Time
Let the sum of money be Rs y
So Amount = y +[( y x 5 x 4 )/100]
But Amount = Rs 900
? 900 = y +(20y)/100
? 900 = 6y / 5
? y = ( 900 x 5) /6
= Rs 750
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