Then, first number = 120% of x = | 120x | = | 6x |
100 | 5 |
Second number = 150% of x = | 150x | = | 3x |
100 | 2 |
∴ Ratio of first two numbers = | ❨ | 6x | : | 3x | ❩ | = 12x : 15x = 4 : 5. |
5 | 2 |
A's new salary = | 115 | of 2k = | ❨ | 115 | x 2k | ❩ | = | 23k |
100 | 100 | 10 |
B's new salary = | 110 | of 3k = | ❨ | 110 | x 3k | ❩ | = | 33k |
100 | 100 | 10 |
C's new salary = | 120 | of 5k = | ❨ | 120 | x 5k | ❩ | = 6k |
100 | 100 |
∴ New ratio | ❨ | 23k | : | 33k | : 6k | ❩ | = 23 : 33 : 60 |
10 | 10 |
Quantity of milk = | ❨ | 60 x | 2 | ❩litres = 40 litres. |
3 |
Quantity of water in it = (60- 40) litres = 20 litres.
New ratio = 1 : 2
Let quantity of water to be added further be x litres.
Then, milk : water = | ❨ | 40 | ❩ | . |
20 + x |
Now, | ❨ | 40 | ❩ | = | 1 |
20 + x | 2 |
⟹ 20 + x = 80
⟹ x = 60.
∴ Quantity of water to be added = 60 litres.
(x x 5) = (0.75 x 8) ⟹ x = | ❨ | 6 | ❩ | = 1.20 |
5 |
Then, | 3x - 9 | = | 12 |
5x - 9 | 23 |
⟹ 23(3x - 9) = 12(5x - 9)
⟹ 9x = 99
⟹ x = 11.
∴ The smaller number = (3 x 11) = 33.
Let the total number of boys in the class be x.
Then, according to the question,
x + 45 = 95
x = 95 - 45 = 50
Hence, the required ratio of total number of boys to total number of girls = B:G = 50:45 = 10:9
Ram : Gopal = 7 : 17 = 49 : 119
Gopal : Krishan = 7 : 17 = 119 : 289
? Ram : Gopal : Krishan = 49 : 119 : 289
? Ram : Krishan = 49 : 289
Thus, 49 : 289 = 490 : N
&there N = 289 x 490 / 49
= Rs. 2890
Let the price of a scooter be Rs. 3x and that of a television set Rs. 2x.
Then, 3x - 2x = 6000
? x = 6000
? Cost of a television set = 2x
= Rs. 12000
? 18 x 18 = y2
? y = ?144 = 12
Let the side of the square be 'a' and let the radius of the circle be 'r'
Then, a2 = ?r2
? a2 / r2 = ?
? a / r = ??
? a : r = ?? : 1
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