Ratio of the speeds of A and B = | 5 | : 1 = 5 : 3. |
3 |
Thus, in race of 5 m, A gains 2 m over B.
2 m are gained by A in a race of 5 m.
80 m will be gained by A in race of | ❨ | 5 | x 80 | ❩m | = 200 m. |
2 |
∴ Winning post is 200 m away from the starting point.
A : C = 100 : 72.
∴ | B | = | ❨ | B | x | A | ❩ | = | ❨ | 80 | x | 100 | ❩ | = | 10 | = | 100 | = 100 : 90. |
C | A | C | 100 | 72 | 9 | 90 |
∴ B can give C 10 points.
Distance covered by B in 9 sec. = | ❨ | 100 | x 9 | ❩m | = 20 m. |
45 |
∴ A beats B by 20 metres.
Raman covers 1 km in 8 min
and suman cover 1 km in 10 min.
If they starts together, then distance covered by suman in 8 min
= (1000/10) x 8 = 800 m
? Raman will beat suman by (1000 - 800 ) m = 200 m
Required distance = (150 - 20) m = 130 m
Required length = (175 + 25)m = 200 m
Start given by A to B = (800 - 725)m = 75 m
Score of A = 100 points
Score of B = 65 points
? A can give (100 - 65 ) = 35 points to B.
Clearly, B covers 18 m in 9 s.
? B's time over the course = 9/18 x 1000 = 500 s
? A' s time over the course = (500 - 9) = 491 s
Clearly, Y covers 140 m in 14 s
? Y' s time over the course = (14/140) x 1000 = 100 s
? X' s time over the course = 100 - 14 = 86 s
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