Ratio of selling price and Cost Price,
SP:CP = 12:9 =4:3
Profit of 3 oranges = Re 1 (Let CP = Re 1)
Profit = 1/3 = 33.33%
and, Discount = 11.11%
Since, CP : SP : MP = 3:4:4.5
Profit doubles that of discount.
So, % point discount = 33.33%-11.11% = 22.22% point.
Total cost of 4 cars = 1 + 2 = 3 lakh
Total SP of 4 cars = 3 x 1.5 = 4.5 lakh
SP of first cars = 1.2 lakh
SP of rest 3 cars = 4.5 - 1.2 = 3.3 lakh
Average SP of all the 3 cars = 1.1 lakh
Setup cost = Rs. 2800
Paper etc. = Rs. 1600
Printing cost = Rs. 3200
Total cost = Rs. 7600
Total sale price = 1500 x 5 = 7500
Let the amount obtained from advertising is "A" then
(7500 - A) - (7600) = 25% of 7500
A= 1975
Charges of 1 call in February = 350 / 150 = 7/3
Charges of 1 call in March = [350 + ( 50 x 1.4) ] / 250
= 420 / 250
= 42 / 25
% Cheapness of a call in march = [(7/3 - 42/25) / 7/3] x 100
= 28%
Let the CP and SP of 1g = Re. 1, then
He spends Rs. 2000 and purchase 2200 g
and he charges Rs. 2000 and sells 1800 g
Profit (%) = [goods left / goods sold ] x 100
= [ 400 / 1800 ] x 100
= 22 2/9 %
Fresh grapes
Water: Pulp = 80% : 20% = 4 : 1
Dry grapes
Water: Pulp = 25% : 75% = 1 : 3
So out of 20 kg dry grapes, Water : Pulp = 5 kg : 15 kg
After adding of water the ratio of water : pulp is same as the fresh grapes = 4 : 1
So after adding water the quantity of Water and Pulp are 60 kg and 15 kg respectively.
Thus to make dry grapes similar to the fresh grapes, Akram requires 55 kg water with 20kg of dry grapes.
So, the profit (%) = (55 / 20) x 100 = 275 %
Let the total profit = 100
Amount left after donation = 50
Amount left after reinvestment = 20
Now, 5y/8 - 3y/8 = 1200
where y is the amount left after reinvestment
? 2x/8 = 1200
? x = 4800
? total profit = 4800 x 5 = 24000
Total cost = Rs. 50,000
Total sale price (or revenue) = (2000 x 9) + (6000 x 10) = 78,000
Profit (%) = [ 28000 / 50000 ] x 100
= 56%
The maximum possible profit = maximum possible difference in SP and CP.
It means SP be maximum and CP be minimum
CP (min) = Rs. 399
19 x m = 399, where m is an integer.
Again SP (max) = Rs. 697, which is very close to 699
Here 697 = 17 k, k is a positive integer.
So, the maximum profit = 697 - 399 = Rs. 298
Let the CP be 100 and % mark up be k% then
MP = 100 + k
100 + k is also expected SP but actual SP = 100 + k / 2
? [(100 + k / 2)] / k = (200 / 3) x 100 (= 66.66%)
? k = 300
? CP = 100 and MP = 400
Finally SP = 400 / 2 = 200
? Discount = 200 / 400 X 100 = 50%
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