The required greatest number is the HCF of 263-7, 935-7, 1383-7
i.e. 256, 928 and 1376 HCF = 32
If (x+2) is the HCF of x2 + ax + b and x2 + cx + d.
Then, (-2)2 -2a +b = (-2)2 -2c + d
b + 2c = 2a + d
Required measure = HCF of 403, 434 and 465
= 31 cm
7 / 8 = 0.875,
6 / 7 = 0.857,
4 / 5 = 0.8 and 5/6 = 0.833
Now, 0.875 > 0.857 > 0.833 > 0.8
So, 7/8 is the greatest
L.C.M = ( L.C.M . of 2, 4, 5, 7) / (H.C.F. of 3, 9, 6, 12)
= 140/3
L. C . M = ( L.C.M of 3, 6, 9 ) / (H.C.F of 4, 7, 8)
= 18 / 1
= 18
H.C.F = ( H.C.F of 1, 3 , 5, 7, 9) / (L.C.M of 2, 4, 6, 8 , 10)
= 1 / 120
L.C.M of 33, 4, 42 and 3 = L.C.M of 33 x 24
= 27 x 16
= 432
H.C.F of 87 and 145 is 29
? L.C.M = ( 87 x 145) / 29
= 435
H.C.F . of 18 and 25 is 1
So, 18 and 25 are co-primes
Copyright ©CuriousTab. All rights reserved.