Given the ages of Sunitha and Pranitha are 40 years and 60 years.

Let before 'm' years, their ages be in the ratio of 3 : 5

ATQ,

40 - m 60 - m = 3 5

=> 200 - 5m = 180 - 3m

=>2m = 20

=> m = 10 years.

Given Karthik?s age = 32 years

Karthik?s son age = 7 years

Difference between their ages = K - S = 32 - 7 = 25 years ?.(1)

Now, required K = 2S ??(2)

Put (2) in (1)

2S - S = 25

=> S = 25 years

Hence, at the age of 25 years of Karthik?s son, Karthik will be twice as his son?s age.

25 - 7 = 18 years

Therefore, after 18 years the father be twice as old as the son.

Let the present ages of Kapil and Avanthi be K & A

Given difference in their ages = K - A = 9 years ...........(1)

After 7 years, K + 7 =  2(A + 7) ......(2)

K + 7 = 2A + 14

K - 2A = 7 ............(3)

K - A = 9 ....(1)

From (1) & (3),

-A = -2

=> A = 2 years

=> K = 9 + 2 = 11 years

Required, age of Kapil after 4 years = 11 + 4 = 15 years.

From the given data,

Manogna?s age be 0 when she was born.

Her father?s age = 38 years

Her mother?s age when Manogna?s brother who is 4 years younger to her was born = 36 years

=> Manogna?s mother age when Manogna was born = 36 - 4 = 32 years

Hence, the difference between the ages of Manogna?s parents = 38 - 32 = 6 years.

Let Reena?s present age be 'K' yrs.
Given:{(K+3) x 4} - {(K-3) x 3)}
=> K = 21 yrs
So her present age is 21 yrs.
Then, her age after 1 year is 22 yrs.

Let C's age be x years.
Then, B's age = 2x years.
A's age = (2x + 2) years.
(2x + 2) + 2x + x = 27
5x = 25 => x = 5
Hence, B's age = 2x = 10 years.