Problems on Ages
- 1. The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).
Options- A. 8, 20, 28
- B. 16, 28, 36
- C. 20, 35, 45
- D. None of these Discuss
Correct Answer: 16, 28, 36
Explanation:
Then, (4x - 8) + (7x - 8) + (9x - 8) = 56
⟹ 20x = 80
⟹ x = 4.
∴ Their present ages are 4x = 16 years, 7x = 28 years and 9x = 36 years respectively.
- 2. A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, then how old is B?
Options- A. 7
- B. 8
- C. 9
- D. 10
- E. 11 Discuss
Correct Answer: 10
Explanation:
∴ (2x + 2) + 2x + x = 27
⟹ 5x = 25
⟹ x = 5.
Hence, B's age = 2x = 10 years.
- 3. The sum of the present ages of a father and his son is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, son's age will be:
Options- A. 12 years
- B. 14 years
- C. 18 years
- D. 20 years Discuss
Correct Answer: 20 years
Explanation:
Then, (60 - x) - 6 = 5(x - 6)
⟹ 54 - x = 5x - 30
⟹ 6x = 84
⟹ x = 14.
∴ Son's age after 6 years = (x+ 6) = 20 years..
- 4. Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Options- A. 2 times
- B.
2 1 times 2 - C.
2 3 times 4 - D. 3 times Discuss
Correct Answer: 2 times
Explanation:
| ∴ | (4x + 8) = | 5 | (x + 8) |
| 2 |
⟹ 8x + 16 = 5x + 40
⟹ 3x = 24
⟹ x = 8.
| Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
| (x + 16) | 24 |
- 5. Ayesha's father was 38 years of age when she was born while her mother was 36 years old when her brother four years younger to her was born. What is the difference between the ages of her parents?
Options- A. 2 years
- B. 4 years
- C. 6 years
- D. 8 years Also asked in: AIEEE, Bank Exams, CAT, GATE, Analyst, Bank Clerk, Bank PO, Database Administrator, IT Trainer
Correct Answer: 6 years
Explanation:
Father's age when Ayesha's brother was born = (38 + 4) years = 42 years.
∴ Required difference = (42 - 36) years = 6 years.
- 6. The ratio of father's age to the son's age is 4 : 1. The product of their ages is 196. the ratio of their ages after 5 years will be?
Options- A. 3 : 1
- B. 10 : 3
- C. 11 : 4
- D. 14 : 5 Discuss
Correct Answer: 11 : 4
Explanation:
Let father's age be 4T and son's age T years.
? 4T x T = 196
? T2 = 49
? T = 7
Father's age after 5 years = (4T + 5) = 33 years
Son's age after 5 years = (T + 5) = 12 years
? Ratio of their ages after 5 years = 33 : 12 = 11 : 4
- 7. Mr. Sohanlal is 4 times as old as his son. Four years later the sum of their ages will be 43 years. The present age of son is?
Options- A. 5 years
- B. 7 years
- C. 8 years
- D. 10 years Discuss
Correct Answer: 7 years
Explanation:
Let the son's present age be x years
Then, (x + 4) + (4x + 4) = 43
? 5x = 35
? x = 7
- 8. The ratio of Vimal's age and Aruna's age is 3 : 5 and sum of their ages in 80 years. The ratio of their ages after 10 years will be?
Options- A. 2 : 3
- B. 1 : 2
- C. 3 : 2
- D. 3 : 5 Discuss
Correct Answer: 2 : 3
Explanation:
? 3x + 5x = 80
? x = 10
Ratio of their ages after 10 years = (3x + 10) : (5x + 10) = 40 : 60 = 2 : 3
- 9. Ratio of Ashok's age to Pradeep's age equal to 4 : 3. Ashok will be 26 years old after 6 years. How old is Pradeep now?
Options- A. 12 years
- B. 15 years
- C. 191/2 years
- D. 21 years Discuss
Correct Answer: 15 years
Explanation:
Let Ashok's age = 4x years and Pradeep's age = 3x years
From question, 4x + 6 = 26
? x = 5
&ther4; Pradeep's age = 3x = 15 years.
- 10. Sachin was twice as old as Ajay 10 years back. How old is Ajay today if Sachin will be 40 years old 10 years later?
Options- A. 20 years
- B. 10 years
- C. 30 years
- D. 15 years Discuss
Correct Answer: 20 years
Explanation:
Let Ajay's age 10 years back be x years.
Then Sachin's age 10 years back = 2x years
? 2x + 20 = 40
? x = 10
? Present age of Ajay = x + 10 = 20 years
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