Then, (100 - 40)% of x = 420.
⟹ | 60 | x x = 420 |
100 |
⟹ x = | ❨ | 420 x 100 | ❩ = 700. |
60 |
Number of students above 8 years of age = (100 - 20)% of x = 80% of x.
∴ 80% of x = 48 + | 2 | of 48 |
3 |
⟹ | 80 | x = 80 |
100 |
⟹ x = 100.
x% of y = | ❨ | x | x y | ❩ | = | ❨ | y | x x | ❩ | = y% of x |
100 | 100 |
∴ A = B.
∴ Required percentage = | ❨ | 11628 | x 100 | ❩% = 57%. |
20400 |
Increase% = | ❨ | 87500 | x 100 | ❩% = 50%. |
175000 |
∴ Required average = | ❨ | 50 | ❩% = 5%. |
10 |
SP - CP = 480
1.2x - x = 480
?0.2x = 480
?x = 2400
Let Cost Price (CP) = x
Then Selling Price(SP) if he sells at profit = x(1+8%) = 1.08x
and SP, if he sells at loss = x(1-8%) = 0.92%
Given, 1.08%-0.92% = Rs12
0.16x = Rs.12
?x = Rs.75
Concentration of Sulphuric acid = 80%
So in a 100cc, Sulphuric acid = 80cc and water = 20cc
Let x be the amount of water added to make concentration of 50%
?80/(100+x) = 50/100
? 80/(100+x) = 1/2
? x = 60cc
Total weight of alloy = 20+20+ 40 = 80g
Weight of tin = 20g
Percentage of tin = 20g/80g x 100
=25%
Final Price = 25 x (1 + 20/100) x (1 + 40/100)
=Rs.25 x 1.2 x 1.4
= Rs. 42
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