∴ logx y = 100
⟹ y = x100
⟹ y = (210)100 [put value of x]
⟹ y = 21000.
log √8 | is equal to: |
log 8 |
1 |
√8 |
1 |
4 |
1 |
2 |
1 |
8 |
1 |
2 |
log √8 | = | log (8)1/2 | = | ½log 8 | = | 1 | . |
log 8 | log 8 | log 8 | 2 |
If logx | ❨ | 9 | ❩ | = - | 1 | , then x is equal to: |
16 | 2 |
- | 3 |
4 |
3 |
4 |
81 |
256 |
256 |
81 |
256 |
81 |
logx | ❨ | 9 | ❩ | = - | 1 |
16 | 2 |
⟹ x-1/2 | = | 9 |
16 |
⟹ | 1 | = | 9 |
√x | 16 |
⟹ √x = | 16 |
9 |
⟹ x = | ❨ | 16 | ❩ | 2 |
9 |
⟹ x = | 256 |
81 |
⟹ log (33 ) = 1.431
⟹ 3 log 3 = 1.431
⟹ log 3 = 0.477
∴ log 9 = log(32 ) = 2 log 3 = (2 x 0.477) = 0.954.
The value of | ❨ | 1 | + | 1 | + | 1 | ❩ | is: |
log3 60 | log4 60 | log5 60 |
Given expression | = log60 3 + log60 4 + log60 5 |
= log60 (3 x 4 x 5) | |
= log60 60 | |
= 1. |
Required answer = [64 log10 2] + 1
= [ 64 x 0.3010 ] + 1
= 19.264 + 1
= 19 + 1
= 20
? loga x = ( logabx) / (logaba)
? The given expression = [[(logabx) / (logaba)] / [( logabx )] - ( logab)
= (1/logaba) - logab = logaab - logab = loga(ab/b)
= logaa = 1
Given Exp.= log23 x log 32 x log34 x log43
= (log3 / log2) x ( log2 / log3) x (log4 / log3) x (log3 / log4) = 1
log2 10 = log 10 / log 2
= 1 / log 2
= 1.0000 / 0.3010
= 1000 / 301
Given Exp. = log [{(9/8) / (27/32)} x 3/4)]
= log [(9/8) x (3/4) x (32/27)]
= log 1
= 0
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