Logarithm problems
- 1. The value of log2log5625 is :
Options- A. 2
- B. 5
- C. 10
- D. 15 Discuss
Correct Answer: 2
- 2. The number of solutions of the equation logx2x2+40log4xx-14log16xx3=0 is:
Options- A. 0
- B. 1
- C. 2
- D. 3 Discuss
Correct Answer: 3
- 3. If a, b, c be the pth, qth and rth terms of a GP then the value of (q-r) log a + (r-p) log b + (p-q) log c is :
Options- A. 0
- B. 1
- C. -1
- D. pqr Discuss
Correct Answer: 0
Explanation:
- 4. The value of log3437 is:
Options- A. 1/3
- B. -3
- C. -1/3
- D. 3 Discuss
Correct Answer: 1/3
Explanation:
- 5. If 5x - 17 = -x + 7, then x = ?
Options- A. 4
- B. 5
- C. 7
- D. 9 Discuss
Correct Answer: 4
Explanation:
Given equation 5x-17 = -x+7
Add 1x to each side of the equation
5x-17+x = -x+7+x
6x=24
x=4
- 6. If A = log321875 and B = log2432187 , then which one of the following is correct?
Options- A. A
- B. A=B
- C. A>B
- D. can't be determined Discuss
Correct Answer: A=B
Explanation:
Given
=> A
Therefore, A = B
- 7. If log 2 = 0.3010 and log 3 = 0.4771, the values of log5 512 is
Options- A. 2.875
- B. 3.875
- C. 4.875
- D. 5.875 Also asked in: Bank Exams, Bank PO
Correct Answer: 3.875
Explanation:
ANS: log5512 = log512/log5 = = = =2.709/0.699 =2709/699 =3.876
- 8. If log 27 = 1.431, then the value of log 9 is
Options- A. 0.754
- B. 0.854
- C. 0.954
- D. 0.654 Also asked in: Bank Exams, Bank PO
Correct Answer: 0.954
Explanation:
log 27 = 1.431
log
= 1.431
3 log 3 = 1.431
log 3 = 0.477
log 9 = log(
)= 2 log 3 = (2 x 0.477) = 0.954
- 9. If log 2 = 0.30103, Find the number of digits in 256 is
Options- A. 17
- B. 19
- C. 23
- D. 25 Also asked in: Bank Exams, Bank PO
Correct Answer: 17
Explanation:
=56*0.30103 =16.85768.
Its characteristics is 16.
Hence, the number of digits in is 17.
- 10. If logaab = x, then logbab = ?
Options- A. 1/x
- B. x/(x+1)
- C. x/(1-x)
- D. x/(x-1) Discuss
Correct Answer: x/(x-1)
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