Let the sum be Rs.P.then
P(1+R/100)^3=6690?(i) and P(1+R/100)^6=10035?(ii)
On dividing,we get (1+R/100)^3=10025/6690=3/2.
Substituting this value in (i),we get:
P*(3/2)=6690 or P=(6690*2/3)=4460
Hence,the sum is rs.4460.
Thus I only or (II and III) give answer.
Correct answer is (D)
Let each installment be Rs.x. Then,
(P.W. of Rs.x due 1 year hence) + (P.W of Rs.x due 2 years hence) + (P.W of Rs. X due 3 years hence) = 7620.
=> x = 3430
Amount of each installment = Rs.3430
Compound Interest on P at 10% for 2 years when interest is compounded half-yearly
=
Simple Interest on P at 10% for 2 years =
Given that difference between compound interest and simple interest = 124.05
=>
P=8000
Clearly, Rate = 5% p.a .,
Time = 3 years
S.I =Rs.1200.
So,Principal
=Rs.(100 x 1200/3x5)
=Rs.8000.
Amount
=Rs.[8000 x (1+5/100)³]
=Rs(8000x21/20x21/20x21/20)
= Rs.9261
C.I
=Rs.(9261-8000)
=Rs.1261.
Interest for 1 year is the same whether it's simple interest or the compound interest.
Now interest of third year = 8575 - 7350 = 1225; means principal for this interest is 7350 if comound interest is takenIf 7350 is the principal interest = 1225
if 100 is the principal interest =(1225/7350) * 100 = 50/3 %
When a thing increases for two successive times the overall increase on initial amount = a + b + (a * b)/100
Therefore overall interest for two years = 50/3 + 50/3 + [(50/3)*(50/3)]/100 = 325/9 %
Therefore amount after 2 years = 100 + 325/9 = 1225/9
If 1225/9 is the amount principal =100
if 7350 is the amount principal =(900/1225)*7350 =5400
So sum = 5400; Rate = 50/3 %
Principal = Rs.16,000;
Time=9 months = 3 quarters;
Amount
=Rs.[16000x(1+5/100)³] =[16000x21/20x21/20x21/20]
= Rs.18522.
C.I
= Rs.(18522 - 16000)
= Rs.2522.
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