Calendar problems
- 1. How often between 11 O'clock and 12 O'clock are the hands of a clock in integral number of minutes apart?
Options- A. 55 times
- B. 56 times
- C. 58 times
- D. 60 times Discuss
Correct Answer: 56 times
Explanation:
As per the given above question , we can say that
At 11 O'clock, the hour hand is 4 spaces apart from the minute hand. Since there are 60 spaces in one hour, so (60 - 4) times, i.e., 56 times the hands of the clock are an integral number of minutes apart.
Hence , required answer is 56 times .
- 2. Number of times the hands of a clock are in a straight line everyday is:
Options- A. 44
- B. 24
- C. 42
- D. 22 Discuss
Correct Answer: 44
Explanation:
We know that, any relative position of the hands of a clock is repeated 11 times in every 12 hours.
? In every 12 hours, hands coincide 11 times and are opposite to each other 11 times.
? In every 12 hours, hands are in a straight line 11 + 11 = 22 times.
? In every 24 hours hands are in a straight line 44 times.
- 3. The watch which gains uniformly is 2 minutes. slow at noon on Sunday and is 4 minutes. 48 seconds. fast at 2 pm on the following Sunday. The watch was correct at:
Options- A. 2 pm on Tuesday
- B. 12 noon on Monday
- C. 1 : 30 pm on Tuesday
- D. 12 : 45 pm on Monday Discuss
Correct Answer: 2 pm on Tuesday
Explanation:
- 4. Number of times 29th day of the month occurs in 400 consecutive years is:
Options- A. 4497
- B. 4800
- C. 4400
- D. None of these Discuss
Correct Answer: 4497
Explanation:
On the basis of above given question , we know that
400 consecutive years contain 97 leap years.
? In 400 consecutive years February has 29 days 97 times and the remaining 11 months have 29th day
400 × 11 = 4400 times
? 29th day of the month occurs ( 4400 + 97 ) = 4497 times.
- 5. If March 2, 1994 was on Wednesday, January 1994 25, was on:
Options- A. Wednesday
- B. Thursday
- C. Tuesday
- D. Monday Also asked in: Bank Exams
Correct Answer: Tuesday
Explanation:
As per the above given question , we can say that
Number of days from January 25, 1994 to March 2, 1994 is
January + February + March = 6 + 28 + 2 = 36 days = 5 weeks + 1 odd day
? Number of odd days = 1
? Day on January 25, 1994 is one day before the day on March 2, 1994.
But March 2, 1994 was on Wednesday.
Therefore , January 1994 25 was on Tuesday
- 6. If a clock strikes 6 times in five seconds, the number of strikes in 10 seconds is:
Options- A. 10
- B. 11
- C. 9
- D. 8 Also asked in: Bank Exams
Correct Answer: 11
Explanation:
- 7. Suresh was born on October 4, 1999. Shashikanth was born 6 days before Suresh. The Independence day of that year fell on Sunday. Which day was Shashikanth born?
Options- A. Tuesday
- B. Wednesday
- C. Monday
- D. Sunday Discuss
Correct Answer: Tuesday
Explanation:
As per the given above question , we have
Birth date of Sashikant = September 28
Difference in number of days from August 15 to September 28 = 16 + 28 = 44
Number of odd days in 44 days = 2 odd days
Hence , Birthday of Shashikant = Sunday + 2 odd days = Tuesday.
- 8. A wall clock gains 2 minutes in 12 hours, while a table clock loses 2 minutes every 36 hours. Both are set right at 12 noon on Tuesday. The correct time when both show the same time next would be:
Options- A. 12 : 30 at night, after 130 days
- B. 12 noon, after 135 days
- C. 1 : 30 at night, after 130 days
- D. 12 midnight, after 135 days Discuss
Correct Answer: 12 noon, after 135 days
Explanation:
- 9. In every 30 minutes the time of a watch increases by 3 minutes. After setting the correct time at 5 am, what time will the watch show after 6 hours?
Options- A. 10 : 54 am
- B. 11 : 30 am
- C. 11 : 36 am
- D. 11 : 42 am Discuss
Correct Answer: 11 : 36 am
Explanation:
As per the given above question , we can say that
In 1 hour it increases by 6 minutes so in 6 hours it increases by 36 minutes.
Thus , required time will be 11 : 42 am .
- 10. A man who went out between 3 and 4 and returned between 8 and 9, found that the hands of the watch had exactly changed places. He returned at:
Options- A. 14 minutes past 8
- B. 21 1 minutes past 8 . 13
- C. 19 2 minutes past 8 . 13
- D. 18 6 minutes past 8 . 13 Discuss
Correct Answer: 18 6 minutes past 8 . 13
Explanation:
As per the given above question , we can say that
1. In 1 min ,minute hand moves 6 Degree
2. In 1 min,hour hand moves 0.5 Degree
Let suppose man went out at y past three i.e. 3 hours y minutes
then, minute hand will be at ( 6y ) Degree from origin.
and hour hand will be at ( 3 × 30 + y × 0.5) Degree = ( 90 + 0.5y ) Degree
Similarly ,man returned at z past eight i.e. 8 hours z minutes
then, minute hand will be at ( 6z ) Degree from origin.
and hour hand will be at ( 8 × 30 + z × 0.5 ) Degree = ( 240 + 0.5z ) Degree
And as per the given condition :-
6y = 90 + 0.5y ...... ( ? )
and 6z = 240 + 0.5z ...... ( ? )
Solve these equations , we get y = 16.36 and z =43.63
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