Speed downstream = 10.5 kmph.
∴ Total time taken = | ❨ | 105 | + | 105 | ❩hours = 24 hours. |
7.5 | 10.5 |
Speed in still water = | 1 | (11 + 5) kmph = 8 kmph. |
2 |
Then, his rate downstream = 2x kmph.
∴ (Speed in still water) : (Speed of stream) = | ❨ | 2x + x | ❩ | : | ❨ | 2x - x | ❩ |
2 | 2 |
= | 3x | : | x |
2 | 2 |
= 3 : 1.
Then, distance covered upstream in 8 hrs 48 min = Distance covered downstream in 4 hrs.
⟹ | ❨ | x x 8 | 4 | ❩ | = (y x 4) |
5 |
⟹ | 44 | x =4y |
5 |
⟹ y = | 11 | x. |
5 |
∴ Required ratio = | ❨ | y + x | ❩ | : | ❨ | y - x | ❩ |
2 | 2 |
= | ❨ | 16x | x | 1 | ❩ | : | ❨ | 6x | x | 1 | ❩ |
5 | 2 | 5 | 2 |
= | 8 | : | 3 |
5 | 5 |
= 8 : 3.
Time taken to travel 68 km downstream = | ❨ | 68 | ❩hrs = 4 hrs. |
17 |
Rate in still water=[(1/2)(u+v)] km/h
Rate of current=[(1/2)(u-v)] km/h
where u= speed of boat in downstream
v=speed of boat in upstream
Speed of boat in still water=[(1/2)(7+13)] =10 km/h
Speed of the stream =[(1/2)(13-7)]=3 km/h
Let the speed of the stream = x km/h
?Speed of boat in still water = 10 km/h
Speed of boat downstream = ( x + 10) km/h
Speed of boat upstream=(10 - x) km/h
? Time taken to travel 26 km downstream=[ 26 / ( 10 + x ) ] h
Time taken to travel 14 km upstream=[ 14 /( 10 - x )] h
? By condition [ 26 / ( 10 + x)]=[ 14 / ( 10 - x)]
? 26(10-x)=14(10+x)
? 260-26x =140 + 14x
? 40x=120
? x = 3 Here, speed of stream = 3 km/h
Speed upstream = (40/8) km/hr = 5 km/hr
Speed downstream = (36/6) km/hr = 6 km/hr
Speed of boat in still water = (5 + 6)/2 km/hr = 5.5 km/hr.
Let the rate against the current be x km/hr.
Then, (12 - x) / 2 = 1.5
? 12 - x = 3
? x = 9 km/hr
Speed of current = 5 - 3.5 = 1.5 km/hr.
So the speed of man along the current = 5 + 1.5 = 6.5 km/hr
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