Number of runs scored more to increse the ratio by 1 is 26 - 14 = 12
To raise the average by one (from 14 to 15), he scored 12 more than the existing average.
Therefore, to raise the average by five (from 14 to 19), he should score 12 x 5 = 60 more than the existing average. Thus he should score 14 + 60 = 74.

Total number of students = 54 x 30
When arranged in rows of 45, number of rows formed are,
54 x 30 45 = 36.

Required average = (67 * 2 + 35 * 2 + 6 * 3) / (2 + 2 + 3)

                           = (134 + 70 + 18) / 7  =  222 / 7 = 31(5/7) years.

One way to deal with fractions is to convert them all to decimals. 

In this case all you would need to do is to see which is greater than 0.5.

Otherwise to see which is greater than ½, double the numerator and see if the result is greater than the denominator. In B doubling the numerator gives us 8, which is bigger than 7. 

Let the number be 'x'.

x + x 2 2 = 11x
x 2= 22x
=> x = 22.

Amithab's total expenditure for Jan - June  = 4200 x 6 = 25200

Expenditure for Feb - June = 25200-1200 = 24000

Expenditure for the months of Feb - July = 24000 + 1500 =25500

The average expenditure = 25500/6 = 4250

     D _  C  _ A          --------(1)

     D > B > C           --------(2)

from (1) and (2)

     D > B > C > A   ---------(3)

Again      E _ B _ A

But B > A, from (3)

So          E > D > B > C > A      [ Since B is the average of E and A so it is eqidistant from both E and A]

3X + 4y = 240
by substitute through options 48 is correct