Area problems
- 1. The edge of three cubes of metal is 3 m, 4 m and 5 m. They are melted and formed into a single cube. Find the edge of the new cube ?
Options- A. 15 m
- B. 4 m
- C. 6 m
- D. 9 m Also asked in: GRE, GATE, CAT, Bank Exams, AIEEE, Bank PO, Bank Clerk
Correct Answer: 6 m
Explanation:
The edge of the new cube is = => a = 6 m.
- 2. A class is 6 meters 24 centimeters in length and 4 meters 32 centimeters in width. Find the least number of square tiles of equal size required to cover the entire floor of the class room ?
Options- A. 115
- B. 117
- C. 116
- D. 114 Also asked in: AIEEE, Bank Exams, CAT, Bank Clerk, Bank PO
Correct Answer: 117
Explanation:
Length = 6 m 24 cm = 624 cm
Width = 4 m 32 cm = 432 cm
HCF of 624 and 432 = 48
Number of square tiles required = (624 x 432)/(48 x 48) = 13 x 9 = 117.
- 3. Calculate the number of bricks, each measuring 25 cm x 15 cm x 8 cm required to construct a wall of dimensions 10 m x 4 cm x 6 m when 10% of its volume is occupied by mortar ?
Options- A. 720
- B. 600
- C. 660
- D. 6000 Also asked in: AIEEE, Bank Exams, CAT, Bank Clerk, Bank PO
Correct Answer: 720
Explanation:
Let the number of bricks be 'N'
10 x 4/100 x 6 x 90/100 = 25/100 x 15/100 x 8/100 x N
10 x 4 x 6 x 90 = 15 x 2 x N => N = 720.
- 4. Chord AB of a circle when extended meets the tangent to the circle at point P. PT is the tangent touching the circle at point T. If lengths of PT and PB are 6 cm and 4 cm respectively, what is the length of PA?
Options- A. 12 cm
- B. 11 cm
- C. 10 cm
- D. 9 cm Also asked in: AIEEE, Bank Exams, CAT
Correct Answer: 9 cm
- 5. Two concentric circles form a ring. The inner and outer circumference of the ring are 352/7 m and 528/7m respectively.Find the width of the ring.
Options- A. 5
- B. 4
- C. 3
- D. 2 Also asked in: Bank Exams, Bank PO
Correct Answer: 4
Explanation:
let the inner and outer radii be r and R meters
then,
= 352/7
=> r = (352/7) * (7/22) * (1/2) = 8m
= 528/7
=> R= (528/7) * (7/22) * (1/2)= 12m
width of the ring = R-r = 12-8 = 4m
- 6. The perimeters of two squares are 40cm and 32 cm. Find the perimeter of a third square whose area is equal to the difference of the areas of the two squares.
Options- A. 12
- B. 24
- C. 36
- D. 48 Also asked in: Bank Exams, Bank PO
Correct Answer: 24
Explanation:
side of first square = 40/4 =10cm
side of second square = 32/4 = 8cm
area of third squre = 10² - 8² = 36 sq cm
side of third square = = 6 cm
required perimeter = 6*4 = 24cm
- 7. A cow s tethered in the middle of a field with a 14feet long rope.If the cow grazes 100 sq feet per day, then approximately what time will be taken by the cow to graze the whole field?
Options- A. 616
- B. 716
- C. 816
- D. 516 Also asked in: Bank Exams, Bank PO
Correct Answer: 616
Explanation:
area of the field grazed = (22/7) * 14 * 14 = 616 sq feet
- 8. Wheels of diameters 7cm and 14cm start rolling simultaneously from x & y which are 1980 cm apart towards each other in opposite directions. Both of them make the same number of revolutions per second. If both of them meet after 10seconds.The speed of the smaller wheel is
Options- A. 22m/s
- B. 33m/s
- C. 44m/s
- D. 55m/s Also asked in: Bank Exams, Bank PO
Correct Answer: 22m/s
Explanation:
let each wheel make x revolutions per sec. Then
distance moved by smaller wheel in 3 revolutions
=
speed of smaller wheel = m/s = 22m/s
- 9. The length of the rectangle is 20% more than its breadth . what will be the ratio of the area of the rectangle to that of the square whose side is equal to the breadth of the rectangle?
Options- A. 2:1
- B. 5:6
- C. 6:5
- D. data is inadequate Also asked in: Bank Exams, Bank PO
Correct Answer: 6:5
Explanation:
Required ratio =
- 10. The perimeter of a square is equal to twice the perimeter of a rectangle of length 8cm and breadth 7cm. What is the circumference of a semicircle whose diameter is equal to the side of the square ?
Options- A. 55.12 cm
- B. 22.54 cm
- C. 42.51 cm
- D. 38.57 cm Also asked in: GRE, GATE, CAT, Bank Exams, AIEEE, Bank PO, Bank Clerk
Correct Answer: 38.57 cm
Explanation:
We know that perimeter of rectangle = 2(l+b) = 2(8+7)= 30cm
Given perimeter of square is twice the perimeter of rectangle = 2(30) = 60cm
Therefore, side of the square is = 1/4 x 60 = 15cm
Circumference of the required semicircle =
=
= 23.57 + 15 = 38.57cm.
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