length of the diagonal = 52 x (15/60) =13m 

sum of length and breadth = 68 x (15/60) = 17m

l 2 + b 2 = 13 o r l + b = 17

area =lb = 1/2[(2lb)] = 1/2[(l+b)² - (l²+b²)] = 1/2[17² -169]

=1/2 x 120 = 60 sq.m

?r 2 = 26 . 64

Total are of all stairs = 50 (20x60 + 30x60)

= 50 (1200 + 1800)

= 50 x 3000

= 150000 sq cm.

Given rate of 100 sq cm = Rs. 4

Then for 150000 sq. cm = ?

=> 4 x 150000/100 = Rs. 6000

Let the length of the rectangle = L cm

Then the breadth of the rectangle = (L - 10) cm

Perimeter of a rectangle = 2(L + B) cm

=> 44 = 2(L + L - 10)

=> 44 = 4L - 20

=> 4L = 64

=> L = 16 cm

=> B = L - 10 = 6 cm

Diagonal =  L 2 + B 2 =  16 2 + 6 2 = 17.08 cm

Other side =  d 2 - s 2=  225 4 - 81 4 =  144 4 = 6 ft

  Area of closet = (6 x 4.5) sq. ft = 27 sq. ft.

Let ABC be the isosceles triangle and AD be the altitude 

Let AB = AC = x. Then, BC = (32 - 2x). 

Since, in an isosceles triangle, the altitude bisects the base,
so BD = DC = (16 - x).
In triangle ADC, A C 2 = A D 2 + D C 2 

? x 2 = 8 2 + 16 - x 2 ? x = 10 

BC = (32- 2x) = (32 - 20) cm = 12 cm. 

Hence, required area =   1 2 * B C * A D = 1 2 * 12 * 8 = 48 c m 2

let x and y be the sides of the rectangle then 

correct area = 105 100 x × 96 100 y 

Error% =  504 500 x y - x y = 4 500 x y %

4 500 x y × 1 x y × 100 = 4 5 = 0 . 8

required area = [14 x 14 - (4 x 1/4 x 22/7 x 7 x 7) ]sq.cm

= 196 - 154 = 42 sq.cm.

perimeter of the plot = 2(90+50) = 280m
no of poles =280/5 =56m

Let the areas of the two parts be x and (700-x) hectares

therefore,  x - 700 - x = 1 5 x + 700 - x 2

  ? 2 x - 700 = 70

  ? x = 385

So, the two parts are 385 and 315.

 Hence, Area of the smaller = 315 hectares