Let the breadth of the rectangle = b mts

Then Length of the rectangle = b + 6 mts

Given perimeter = 84 mts

2(L + B) = 84 mts

2(b+6 + b) = 84

2(2b + 6) = 84

4b + 12 = 84

4b = 84 - 12

4b = 72

b = 18 mts

=> Length = b + 6 = 18 + 6 = 24 mts

Now, required Area of the rectangle = L x B = 24 x 18 = 432 sq. mts

Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm. 

Area of each tile =  41 × 41 c m 2  

Required number of tiles  =  1517 × 902 41 × 41= 814

Length of the wire fencing = perimeter = 2(90 + 50) = 280 metres

Two poles will be kept 5 metres apart. Also remember that the poles will be placed along the perimeter of the rectangular plot, not in a single straight line which is very important.

Hence number of poles required = 280 / 5 = 56

Perimeter of the rectangle is given by 3000/10 = 300 mts

But we know,

The Perimeter of the rectangle = 2(l + b)

Now,

2(8x + 7x) = 300

30x = 300

x = 10

Required, Area of rectangle = 8x x 7x = 56 x 100 = 5600 sq. mts.

Let x and y be the length and breadth of the rectangle respectively.
Then, x - 4 = y + 3 or x - y = 7 ----(i)
Area of the rectangle =xy; Area of the square = (x - 4) (y + 3)
(x - 4) (y + 3) =xy <=> 3x - 4y = 12 ----(ii)
Solving (i) and (ii), we get x = 16 and y = 9.
Perimeter of the rectangle = 2 (x + y) = [2 (16 + 9)] cm = 50 cm.

distance covered in 1 revolution = 2 ?r = 2 x (22/7) x 20 = 880/7 cm
required no of revolutions = 17600 x (7/880) = 140

Distance covered in one revolution =  88 × 1000 1000= 88m. 

2 ?R 2 = 88 ? 2 × 22 7 × R = 88 ? R = 88 × 7 44

let the radius of the pool be Rft

Radius of the pool including the wall = (R+4)ft

Area of the concrete wall = ? R + 4 2 - R 2= ? R + 4 + R R + 4 - R = 8 ? R + 2 sq feet

=> 8 ? R + 2 = 11 25 ?R 2 = > 11 R 2 = 200 R + 2

Radius of the pool R = 20ft