let the diagonals of the squares be 2x and 5x respectively

ratio of their areas =  1 2 * 2 x 2 : 1 2 * 5 x 2= 4:25

Area of a square with side a = a² sq unts

Area of a triangle with base a = (1/2) * a * h sq.unts

a² =1/2 *a *h

=> h = 2a

altitude of the triangle is 2a

Perimeter of a square p=4s ,where s=length of its side 

=> p=4(14)=56 feets 

Area  of a square A = s x s

=> A=196

The perimeter is 56 feet, and the area is 196 square feet.

let each have base = b and height = h
then p = b*h, R = b*h and T = (1/2) * b*h
so P = R, P = 2T and T = (1/2)*R are all correct statements

let the side of the square be x meters
length of two sides = 2x meters
diagonal =  2 x= 1.414x m

saving on 2x meters = .59x m

saving % =  0 . 59 x 2 x * 100%

= 30% (approx)

A=LB