Alligation or Mixture problems
- 1. Find the quantity of rice @ Rs. 10 per kg. which should be mixed with 25 kgs of rice @ Rs. 8 per kg, so that on selling the mixture @ Rs. 15 per kg there is 80% profit.
Options- A. 6 kgs
- B. 7 kgs
- C. 3 kgs
- D. 5 kgs Discuss
Correct Answer: 5 kgs
Explanation:
Cost price of the mixture = 15 × (100 / 180) = Rs. 25/3 per kg
(Quantity of rice @ Rs. 8 per kg) / (Quantity of rice @ Rs.10 per kg) = (5 / 3) / (1/3) = 1/5
Quantity of rice @ Rs. 10 per kg = 25 × (1/ 5) = 5 kgs.
- 2. A person has two solutions of sugar with 30% and 50% concentration respectively. In what proportion should he mix two solutions to get 45% concentration in the resulting mixture?
Options- A. 1 : 3
- B. 3 : 1
- C. 2 : 3
- D. 3 : 2 Discuss
Correct Answer: 1 : 3
Explanation:
He should mix 30% and 50% in the ratio 5 : 15 or 1 : 3.
( 30% Solution ) / (50% Solution) = 1 / 3 or 1 : 3
- 3. A merchant has 160 kgs of wheat. He sells a part of it at 10% profit and the rest of 6% loss. If he incurs 4% loss on the whole, find the quantity for each part.
Options- A. 120 kgs
- B. 140 kgs
- C. 150 kgs
- D. 160 kgs Discuss
Correct Answer: 140 kgs
Explanation:
According to figure we can find that the ration would be 1 : 7.
Quantity sold at 10% profit = 1 / (1 + 7)× 160 = 20 kgs.
Quantity sold at 6% loss = (160 ? 20) = 140 kgs.
- 4. A man bought a certain quantity of sugar for Rs. 8000. He sells one-fourth of it at 20% loss. At what per cent profit should he sell the remainder stock so as to make an overall profit of 20%?
Options- A. 20%
- B. 30%
- C. 35%
- D. 40% Also asked in: Bank Exams
Correct Answer: 30%
Explanation:
Let the remainder stock be sold at P% profit.
(P - 20) / 30 = ((1 / 4) / (3 / 4))
or (P ? 20) = 30 × (1 / 3)
or P = 20 + 10
P = 30% profit.
- 5. A person has Rs. 5000. He invests a part of it at 3% per annum and the remainder at 8% per annum simple interest. His total income in 3 years is Rs. 750. Find the sum invested at different rates of interest.
Options- A. Rs. 2000 and Rs. 3000
- B. Rs. 2500 and Rs. 2500
- C. Rs. 3000 and Rs. 2000
- D. Rs. 2750 and Rs. 2250 Discuss
Correct Answer: Rs. 3000 and Rs. 2000
Explanation:
Average rate of interest = (100 * 750) / (5000 * 3) = 5% per annual
Investment at 3% per annual = 3 / (3 + 2) × 5000 = Rs. 3000 Investment at 8% per annual = 2 / (3 + 2) × 5000 = Rs. 2000
- 6. The average daily wages of staff, consisting of supervisors and labourers, of a company is Rs. 50. The average wages of supervisors is Rs. 150 while that of labourers is Rs. 40 per day. If the number of supervisors is 15, find the number of labourers in the company.
Options- A. 150
- B. 175
- C. 180
- D. 200 Discuss
Correct Answer: 150
Explanation:
As per figure we can calculate the ration as below.
Number of supervisors / Number of labourers = (10 / 100) = 1/10
Total number of labourers = Total no. of supervisors × 10
= 15 × 10 = 150.
- 7. A sum of Rs. 70 is divided among 10 children. Each boy gets Rs. 10 whereas a girl gets Rs. 5. If the number of boys is 4, find the number of girls.
Options- A. 6
- B. 7
- C. 8
- D. 9 Discuss
Correct Answer: 6
Explanation:
Number of girls / Number of boys = (3 / 2)
Number of girls = (3 / 2) × 4 = 6
- 8. A vessel contains 80 litres of milk. 16 litres of milk was taken out of the vessel and replaced by water. Then 16 litres of mixture was withdrawn and again replaced by water. The operation was repeated for third time. How much milk is now left in the vessel?
Options- A. 96.40 litres
- B. 50.36 litres
- C. 40.96 litres
- D. 32.76 litres Discuss
Correct Answer: 40.96 litres
Explanation:
Amount of milk left = 80 [1 - (16 / 80)]3 = 80 (4 / 5)3
80 × (64 / 125) = 40.96 liters.
- 9. In what ratio must a grocer mix two varieties of tea worth Rs. 60 a kg and Rs. 65 a kg so that by selling the mixture at Rs. 68.20 a kg he may gain 10%?
Options- A. 4 : 5
- B. 3 : 5
- C. 3 : 4
- D. 3 : 2 Discuss
Correct Answer: 3 : 2
Explanation:
S.P. of 1 kg mixture = Rs. 68.20, Gain % = 10 %
Hence, C.P. of 1 kg mixture = (100 / 110) x 68 20 . = Rs. 62
By the rule of alligation
Hence, required ratio = 3 : 2
- 10. A shopkeeper has 100 kgs of tea. He sells a part of it at 20% profit and the rest at 5% loss. If his overall profit is 10%, find the quantity for each part.
Options- A. 20 kgs
- B. 25 kgs
- C. 30 kgs
- D. 40 kgs Discuss
Correct Answer: 20 kgs
Explanation:
As per figure, we can calculate as below.
Quantity sold at 20% profit = 3 / (3 + 2) × 100 = 60 kgs.
Quantity sold at 5% loss = (100 ? 60) = 40 kgs.
More in Aptitude:
Programming
Copyright ©CuriousTab. All rights reserved.