Telescoping Product of the Form (1 − 1/k) Compute the product (1 − 1/3) (1 − 1/4) (1 − 1/5) … (1 − 1/n) for integer n ≥ 3.

Difficulty: Easy

Correct Answer: 2/n

Explanation:


Introduction / Context:
Products of the form (1 − 1/k) are best handled by rewriting as simple fractions that telescope. This saves time and avoids expanding long products manually.



Given Data / Assumptions:

  • Product index runs from k = 3 to k = n, where n ≥ 3.
  • Each term simplifies to (k − 1)/k.


Concept / Approach:
Rewrite each factor and cancel successive numerator–denominator pairs. Only the earliest numerator and the last denominator survive the cancellations, revealing a compact closed-form expression.



Step-by-Step Solution:
(1 − 1/k) = (k − 1)/k.Product from k = 3 to n: Π (k − 1)/k = (2/3) * (3/4) * (4/5) * … * ((n − 1)/n).Telescoping leaves 2/n (all intermediate factors cancel).



Verification / Alternative check:
Test n = 5: (1 − 1/3)(1 − 1/4)(1 − 1/5) = (2/3)(3/4)(4/5) = 2/5 = 2/n, confirming the formula.



Why Other Options Are Wrong:
1/n misses the factor 2; 2(n − 1)/n and 2(n + 1)/n do not arise from telescoping; 1/(n − 1) is a common mis-cancellation error.



Common Pitfalls:
Dropping the initial 2/3 factor; misaligning the cancellation ends; attempting to sum instead of multiplying.



Final Answer:
2/n


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