Difficulty: Easy
Correct Answer: 4/11
Explanation:
Introduction / Context:
We select one character uniformly from a word and ask for the chance it is a vowel. Repetitions matter in counting because each occurrence is a distinct favourable outcome.
Given Data / Assumptions:
Concept / Approach:
Count total characters and the number of vowel occurrences (including duplicates). Probability = vowel count / 11.
Step-by-Step Solution:
Letters with multiplicities: P(1), R(1), O(1), B(2), A(1), I(2), L(1), T(1), Y(1).Vowels present (with counts): A(1), O(1), I(2) → 4 vowels.Probability = 4/11.
Verification / Alternative check:
Consonant count = 7; 4 + 7 = 11 confirms total.
Why Other Options Are Wrong:
3/11 or 2/11 undercount vowel multiplicities; 0 ignores vowels entirely.
Common Pitfalls:
Counting distinct vowel types instead of occurrences; duplicates (I appears twice) must be included.
Final Answer:
4/11
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