Difficulty: Easy
Correct Answer: filter
Explanation:
Introduction / Context:
Power supplies convert AC mains into a usable DC voltage. After the diode rectifier creates a pulsating DC waveform, additional circuitry is needed to “smooth” the ripple and produce a steadier DC before fine regulation. This question checks whether you can correctly identify the block that performs the smoothing function in the classic supply chain.
Given Data / Assumptions:
Concept / Approach:
The filter stage is designed to attenuate the AC ripple component present at the rectifier output. Common filters include a large reservoir capacitor (C filter), an LC choke-input filter, or a π (C–L–C) network. While a regulator improves voltage stability and load/line regulation, the chief “smoothing” action that turns pulsating DC into a much flatter DC is the job of the filter.
Step-by-Step Solution:
Rectifier: converts AC to pulsating DC (high ripple).Filter: capacitor(s)/inductor(s) charge and discharge to fill gaps between peaks, reducing ripple.Regulator: trims and stabilizes the already-smoothed DC to a precise level.Therefore, the block indicating a smoothed DC output is the filter stage.
Verification / Alternative check:
Observe waveforms on an oscilloscope: rectifier output shows large ripple; adding a filter capacitor markedly flattens the waveform. Adding a regulator then further stabilizes the DC level with minimal remaining ripple.
Why Other Options Are Wrong:
Common Pitfalls:
Final Answer:
filter
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