The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:

Difficulty: Medium

Correct Answer: 4.14% per year

Explanation:

Given

  • Initial population P0 = 1,75,000
  • Population after 10 years P10 = 2,62,500

Concept

The average annual percent increase is the CAGR: ( 𝑃 10 / 𝑃 0 ) 1 / 10 βˆ’ 1 (P 10 ​ /P 0 ​ ) 1/10 βˆ’1.


Step 1: Compute the growth factor
Growth factor = 2 , 62 , 500 1 , 75 , 000 = 1.5 1,75,000 2,62,500 ​ =1.5


Step 2: Compute CAGR
CAGR = 1.5 1 / 10 βˆ’ 1 1.5 1/10 βˆ’1Using ln/exponent: ln(1.5) β‰ˆ 0.405465; divide by 10 β‡’ 0.0405465; exp β‡’ 1.04141CAGR β‰ˆ 1.04141 βˆ’ 1 = 0.04141 = 4.14% per year


Final Answer
Average percent increase β‰ˆ 4.14% per year.

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