Difficulty: Easy
Correct Answer: freezing (melting)
Explanation:
Introduction / Context:Ammonia (R-717) is a widely used refrigerant in industrial systems. Knowing its key thermophysical properties—boiling, freezing, and critical points—is essential for safe and reliable design.
Given Data / Assumptions:
Concept / Approach:Compare the given temperature with known characteristic temperatures. Because −77.7°C is far below the normal boiling point, it aligns with the freezing (melting) point of ammonia, the temperature at which liquid ammonia solidifies at 1 atm.
Step-by-Step Solution:
Recall key points: T_boil,1atm ≈ −33.3°C; T_freeze ≈ −77.7°C; T_critical ≈ 132.4°C (critical temperature).Match the given −77.7°C to these known values.Conclude that −77.7°C corresponds to the freezing (melting) point.Therefore the blank should be “freezing (melting)”.Verification / Alternative check:Consult standard property tables for R-717 to confirm the numerical values; industrial design texts list these constants consistently.
Why Other Options Are Wrong:
Common Pitfalls:Confusing boiling and freezing points for substances with negative values; always cross-reference known constants.
Final Answer:freezing (melting)
Discussion & Comments