Difficulty: Easy
Correct Answer: recombination across the junction interface
Explanation:
Introduction / Context:
Creating a pn junction by joining p-type and n-type semiconductors triggers charge-carrier movement that sets up a depletion region and a built-in electric field. Recognizing the first microscopic events at the interface helps explain rectification and diode I-V characteristics.
Given Data / Assumptions:
Concept / Approach:
Once the regions touch, majority carriers diffuse: electrons from the n-side move into the p-side, and holes from the p-side move into the n-side. When an electron and a hole meet, they recombine, eliminating free carriers in a narrow zone. This creates the depletion region, leaving behind fixed ionized donors and acceptors whose charges establish the built-in electric field and potential barrier. The process continues until drift due to the electric field balances diffusion, reaching equilibrium.
Step-by-Step Solution:
Verification / Alternative check:
Standard band diagrams show band bending and a built-in potential V_bi with a space-charge region depleted of mobile carriers, consistent with initial recombination and diffusion.
Why Other Options Are Wrong:
Common Pitfalls:
Thinking that breakdown or large currents are necessary to form depletion; in reality, equilibrium diffusion and recombination suffice.
Final Answer:
recombination across the junction interface
Discussion & Comments