Plane Wave in a Dielectric: A plane electromagnetic wave travels in a medium with relative permittivity εr = 9 (μr ≈ 1). How does its speed compare to free space?

Difficulty: Easy

Correct Answer: reduced by a factor of 1/3

Explanation:


Introduction / Context:
Propagation velocity of electromagnetic waves in a lossless dielectric depends on the medium’s permittivity and permeability. This question reinforces the relationship between speed, refractive index, and relative permittivity.



Given Data / Assumptions:

  • Relative permittivity εr = 9.
  • Relative permeability μr ≈ 1 (non-magnetic).
  • Free-space speed c ≈ 3 × 10^8 m/s.


Concept / Approach:

The wave speed in a medium is v = c / sqrt(εr μr). For μr ≈ 1, v = c / sqrt(εr). The refractive index n = sqrt(εr μr) = sqrt(εr) when μr = 1.



Step-by-Step Solution:

Compute sqrt(εr): sqrt(9) = 3.Thus v = c / 3.Therefore, speed is reduced to one-third of free-space speed.


Verification / Alternative check:

Equivalently, n = 3 implies v = c/n = c/3. This matches standard optics/electromagnetics relations.



Why Other Options Are Wrong:

  • Increased by 9 or 3: contradicts v = c/√εr.
  • Unchanged: only true for εr = 1.
  • Reduced by 1/9: would require εr = 81.


Common Pitfalls:

  • Confusing phase velocity scaling with εr instead of √εr.
  • Assuming μr ≠ 1 without being given.


Final Answer:

reduced by a factor of 1/3

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