Plane Wave in a Dielectric: A plane electromagnetic wave travels in a medium with relative permittivity εr = 9 (μr ≈ 1). How does its speed compare to free space?
Electronics and Communication Engineering
Electromagnetic Field Theory
Difficulty: Easy
Choose an option
-
Aincreased by a factor of 9
-
Bincreased by a factor of 3
-
Cunchanged
-
Dreduced by a factor of 1/3
-
Ereduced by a factor of 1/9
Answer
Correct Answer: reduced by a factor of 1/3
Explanation
Introduction / Context:Propagation velocity of electromagnetic waves in a lossless dielectric depends on the medium’s permittivity and permeability. This question reinforces the relationship between speed, refractive index, and relative permittivity.
Given Data / Assumptions:
- Relative permittivity εr = 9.
- Relative permeability μr ≈ 1 (non-magnetic).
- Free-space speed c ≈ 3 × 10^8 m/s.
Concept / Approach:
The wave speed in a medium is v = c / sqrt(εr μr). For μr ≈ 1, v = c / sqrt(εr). The refractive index n = sqrt(εr μr) = sqrt(εr) when μr = 1.
Step-by-Step Solution:
Compute sqrt(εr): sqrt(9) = 3.Thus v = c / 3.Therefore, speed is reduced to one-third of free-space speed.Verification / Alternative check:
Equivalently, n = 3 implies v = c/n = c/3. This matches standard optics/electromagnetics relations.
Why Other Options Are Wrong:
- Increased by 9 or 3: contradicts v = c/√εr.
- Unchanged: only true for εr = 1.
- Reduced by 1/9: would require εr = 81.
Common Pitfalls:
- Confusing phase velocity scaling with εr instead of √εr.
- Assuming μr ≠ 1 without being given.
Final Answer:
reduced by a factor of 1/3