Difficulty: Easy
Correct Answer: Reactions with high activation energies are very temperature sensitive.
Explanation:
Introduction / Context:
Basic kinetic and equilibrium concepts predict how reactions respond to temperature and energy inputs, and what “equilibrium” really means at the molecular level.
Given Data / Assumptions:
Concept / Approach:
(a) follows directly from Arrhenius law: larger Ea yields larger fractional change in k for a given temperature change. (b) is incorrect because equilibrium is dynamic (forward and reverse rates equal but nonzero). (c) is misleading; light supplies energy to access excited states but is not a catalyst in the classical sense (a catalyst is regenerated and lowers Ea). (d) is incorrect; molecules must meet or exceed Ea to react.
Step-by-Step Solution:
Apply Arrhenius to compare sensitivity: higher Ea → stronger temperature dependence → (a) is true.Recall the definition of equilibrium: dynamic, not static → (b) false.Clarify photochemistry: light initiates reactions but is not a catalyst → (c) false as phrased.Activation criterion: energy must be ≥ Ea → (d) false.
Verification / Alternative check:
Plot ln k versus 1/T; steeper slope (−Ea/R) for higher Ea confirms greater sensitivity.
Why Other Options Are Wrong:
Common Pitfalls:
Final Answer:
Reactions with high activation energies are very temperature sensitive.
Discussion & Comments