Difficulty: Easy
Correct Answer: 13% cementite and 87% ferrite
Explanation:
Introduction / Context:
Pearlite is the lamellar mixture formed when austenite of eutectoid composition transforms at about 727°C in plain-carbon steel. Understanding its phase fractions is essential for interpreting microstructures, mechanical properties, and heat-treatment responses in steels.
Given Data / Assumptions:
Concept / Approach:
At the eutectoid composition (~0.76–0.8% C), the austenite transforms to pearlite. Applying the lever rule between ferrite (≈0.02% C at room temperature) and cementite (6.67% C) yields approximately 12–13% cementite and 87–88% ferrite by weight in pearlite. These fractions govern hardness and strength; more cementite increases hardness and brittleness, while ferrite provides ductility.
Step-by-Step Solution:
Identify phases: ferrite + cementite in lamellae.Use eutectoid composition and end-member carbon contents to estimate fractions.Lever rule leads to about 12.5–13% cementite and 87–87.5% ferrite by weight.Therefore, the best answer is 13% cementite and 87% ferrite.
Verification / Alternative check:
Metallography references often quote pearlite as roughly 1/8 cementite and 7/8 ferrite by weight—consistent with option (b).
Why Other Options Are Wrong:
(a) confuses carbon content with cementite fraction. (c) inverts the correct proportions. (d) states cementite’s stoichiometric carbon, not pearlite composition. (e) 50/50 by weight is not supported by the lever rule.
Common Pitfalls:
Mixing up weight and volume fractions; the lamellar spacing affects hardness but not the overall phase fractions at a given composition.
Final Answer:
13% cementite and 87% ferrite
Discussion & Comments