Controller design basics: for a proportional–derivative (P–D) controller, what is the standard transfer function form in the Laplace domain?
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AKc(1+τD s)
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BKc(1 +1/τD s)
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CKc τD s
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DKc/τD s
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EKc/(1 + τD s)
Answer
Correct Answer: Kc(1+τD s)
Explanation
Introduction / Context:Classical controllers—P, PI, PD, and PID—are building blocks of feedback control. Recognizing their transfer functions is essential for frequency response design, time-domain tuning, and implementation in analog or digital form.
Given Data / Assumptions:
- P–D controller includes proportional and derivative actions only.
- Laplace transform conventions are standard.
- Kc is controller gain; τD is derivative time (seconds).
Concept / Approach:The ideal PD controller has transfer function Gc(s) = Kc(1 + τD s). The proportional term Kc sets overall gain. The derivative term Kc τD s anticipates changes by acting on the slope of the error, adding phase lead and improving transient performance. Practical implementations include a small high-frequency roll-off (a filter), but the canonical ideal form remains Kc(1 + τD s).
Step-by-Step Solution:Write the ideal PD action: u(t) = Kc[e(t) + τD de/dt].Take Laplace transform: U(s)/E(s) = Kc(1 + τD s).Match to the option list and select Kc(1 + τD s).
Verification / Alternative check:Tuning correlations (e.g., Ziegler–Nichols variants) and frequency response analysis use the same PD transfer form; hardware realizations often add a derivative filter term 1/(1 + τf s) to limit noise amplification.
Why Other Options Are Wrong:Kc(1 + 1/τD s): Dimensionally inconsistent; additive term should be τD s.Kc τD s: Pure derivative, missing proportional path.Kc/τD s or Kc/(1 + τD s): Resemble integrator or lag forms, not PD.
Common Pitfalls:Using an “ideal” derivative without filtering causes noise amplification; always include a small roll-off in practice.
Final Answer:Kc(1+τD s)