Contract sharing — three workers A, B, C paid $575: A and C together are supposed to complete 19/23 of the job. Assuming payment is proportional to actual work share, how much should B be paid?

Introduction / Context:
This is a direct work-sharing allocation. The total contract value is known. When the shares of the work completed by some parties are known, the remainder belongs to the other party, and payment follows the same proportion.

Given Data / Assumptions:

• Total amount for the full work = $575.
• A + C together do 19/23 of the work.
• Hence B does the remaining 4/23 of the work.
• Payment is proportional to work completed.

Concept / Approach:
The person's pay = (their fraction of total work) * (total contract amount). Compute B's fraction and multiply by $575.

Step-by-Step Solution:
Work share of A + C = 19/23.Work share of B = 1 − 19/23 = 4/23.B's pay = (4/23) * 575.Compute 575 / 23 = 25, hence B's pay = 4 * 25 = $100.

Verification / Alternative check:
A + C together get (19/23)*575 = 19*25 = $475. B gets $100. The sum $475 + $100 = $575, confirming consistency.

Why Other Options Are Wrong:

• $210 and $200 correspond to larger fractions than 4/23; they overpay B.
• $475 is the share for A + C, not for B.

Common Pitfalls:

• Mistaking 19/23 as B's share or forgetting that all shares must sum to 1.

Final Answer:
$100