Difficulty: Medium
Correct Answer: Parallel RL circuit (inductive behavior dominates)
Explanation:
Introduction / Context:
Recognizing how RLC networks simplify away from resonance is crucial for quick design estimates. For a parallel RLC, behavior hinges on which susceptance (capacitive or inductive) dominates at a given frequency relative to resonance.
Given Data / Assumptions:
Concept / Approach:
Parallel admittance Y = G + j(B_C - B_L), where B_C = ωC and B_L = 1/(ωL). At low frequency, 1/(ωL) is large while ωC is small, so B_L dominates and B ≈ -1/(ωL), which is inductive. Therefore, the circuit behaves like an RL in parallel, with current lagging voltage and an overall inductive character.
Step-by-Step Solution:
1) Write susceptances: B_C = ωC; B_L = 1/(ωL).2) Evaluate at ω < ω0: B_L >> B_C, so net B is negative (inductive).3) Parallel circuit with inductive dominance behaves like a parallel RL.4) Choose option indicating parallel RL behavior.
Verification / Alternative check:
At high frequency (above resonance), ωC dominates and the behavior flips to capacitive (parallel RC-like). This complementary behavior around resonance confirms the reasoning.
Why Other Options Are Wrong:
Parallel RC (option B) describes above-resonance behavior, not below. “Purely resistive” is only at exact parallel resonance (ideally) when reactive currents cancel. Option C is unrelated to the below-resonance condition.
Common Pitfalls:
Accidentally importing series-circuit intuition (where below resonance is capacitive). Parallel and series cases invert the qualitative dominance.
Final Answer:
Parallel RL circuit (inductive behavior dominates).
Discussion & Comments