Brewster angle for parallel (p-) polarization: air (n1 = 1) to paraffin with εr = 3 (n2 = √3). Find θB.

Difficulty: Easy

Correct Answer: 60°

Explanation:


Introduction / Context:
The Brewster angle is the angle of incidence at which the reflected component of a parallel (p-) polarized wave is zero at a dielectric interface. It is a fundamental optics and electromagnetics concept used in polarization control and anti-reflection design.



Given Data / Assumptions:

  • Incidence from air (n1 = 1) onto paraffin with relative permittivity εr = 3.
  • Refractive index of paraffin: n2 = √εr = √3 ≈ 1.732 (assuming μr = 1).
  • Parallel polarization (p-pol) and non-magnetic media.


Concept / Approach:

Brewster angle for p-polarization is θB = arctan(n2/n1). With air to dielectric, θB depends only on the refractive index ratio (if μr ≈ 1).



Step-by-Step Solution:

Compute refractive index: n2 = √3 ≈ 1.732.Apply formula: θB = arctan(n2/n1) = arctan(1.732) ≈ 60°.Thus, the Brewster angle is 60°.


Verification / Alternative check:

Snell’s law and Fresnel coefficients confirm that for p-polarization, the reflection coefficient goes to zero at θB where transmitted and reflected rays are orthogonal, which occurs at arctan(n2/n1).



Why Other Options Are Wrong:

  • 0°, 30°, 45°: do not satisfy arctan(√3) ≈ 60°.
  • 75°: too large for n2/n1 = √3; arctan growth is slower than linear.


Common Pitfalls:

  • Using s-polarization formula (no Brewster zero for s-pol at dielectric-dielectric).
  • Using θB = arctan(n1/n2) (inverted ratio) which would be incorrect for incidence from air to denser medium.


Final Answer:

60°

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