The inner circumference of a circular race track is 440 m. The track is 14 m wide (uniform width). Find the radius of the outer circle in metres (m), assuming pi = 22/7.

Introduction / Context:
This question uses the circumference formula of a circle and the idea of a “ring” (track) with uniform width. The inner circumference gives the inner radius. Since the track is 14 m wide, the outer radius is simply inner radius + 14. The key is solving 2*pi*r = 440 correctly and then adding the width in the correct direction (radius, not diameter).

Given Data / Assumptions:

• Inner circumference C_inner = 440 m
• Track width = 14 m
• pi = 22/7
• C = 2*pi*r
• Outer radius = inner radius + 14

Concept / Approach:
Use C_inner = 2*pi*r_inner to find r_inner. Then r_outer = r_inner + width. Keep everything in metres and do not confuse width with diameter change (diameter increases by 2*width, but radius increases by width).

Step-by-Step Solution:
C_inner = 2*pi*r_inner440 = 2*(22/7)*r_inner = (44/7)*r_innerr_inner = 440*(7/44) = 10*7 = 70 mr_outer = r_inner + 14 = 70 + 14 = 84 m

Verification / Alternative check:
Quick check: if r_inner is 70, inner circumference = 2*(22/7)*70 = 2*22*10 = 440, correct. Adding width 14 to radius must give 84, which is reasonable for the outer boundary of a 14 m wide track.

Why Other Options Are Wrong:
70 m is just the inner radius (not outer). 44 m or 24 m typically come from dividing by pi incorrectly. 54 m can appear if someone subtracts width instead of adding. 44 m may also come from confusing circumference with diameter directly.

Common Pitfalls:
Forgetting to use 2*pi*r. Confusing radius with diameter. Adding 2*14 to the radius (that would be for diameter). Using pi = 3.14 while options are based on 22/7 exact arithmetic.

Final Answer:
84 m