Difficulty: Medium
Correct Answer: + and x, 4 and 6
Explanation:
Introduction / Context:
This problem asks you to make a false statement true by applying two precise edits to the left-hand side (LHS): (1) swap a pair of operators globally and (2) interchange a named pair of digits wherever they occur. Such items test rule application, operator precedence, and careful sequencing of edits, which are common in mathematical-operations reasoning questions.
Given Data / Assumptions:
Concept / Approach:
For each option, first swap all instances of the named operators, then swap the specified digits throughout the LHS, and finally evaluate. The correct option yields 16 exactly, matching the RHS.
Step-by-Step Solution:
Consider Option C: “+ and x, 4 and 6”.Operator swap (+ ↔ ×): the LHS 6 × 4 + 2 becomes 6 + 4 × 2.Digit swap (4 ↔ 6) globally in the LHS: 6 ↔ 4 turns 6 + 4 × 2 into 4 + 6 × 2.Evaluate with precedence: 6 × 2 = 12; then 4 + 12 = 16.The edited LHS equals 16, so the equality holds.
Verification / Alternative check:
Option A is incomplete (mentions “and 4” only), so it cannot define a valid digit swap pair.Option B (“+ and x, 2 and 4”) produces 6 + 4 × 2 → swap 2 ↔ 4 → 6 + 2 × 4 = 14, not 16.Option D (“None of these”) is false because Option C has already produced a valid equality.
Why Other Options Are Wrong:
They either fail to specify a coherent digit pair or, after correct transformation, evaluate to a number different from 16 (typically 14 or 26 due to precedence effects).
Common Pitfalls:
Final Answer:
+ and x, 4 and 6.
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