Units – Stoke (St) for Kinematic Viscosity Definition: One stoke equals 1 cm^2/s, which is numerically equal to 10^-4 m^2/s in SI units.

Introduction:
This question assesses familiarity with unit conversions for kinematic viscosity, a parameter central to laminar–turbulent characterization and diffusion processes in fluids.

Given Data / Assumptions:

• 1 stoke (St) = 1 cm^2/s by definition.
• SI base for kinematic viscosity is m^2/s.

Concept / Approach:

Convert square centimeters to square meters. Since 1 cm = 10^-2 m, 1 cm^2 = (10^-2 m)^2 = 10^-4 m^2. Therefore 1 St = 10^-4 m^2/s.

Step-by-Step Solution:

Verification / Alternative check:

Compare with centistoke: 1 cSt = 10^-2 St = 10^-6 m^2/s, which is consistent with common values for light oils and water at moderate temperatures.

Why Other Options Are Wrong:

10^-2, 10^-3, and 10^-6 m^2/s are inconsistent with the squared length conversion and are orders of magnitude off.

Common Pitfalls:

Forgetting that the conversion is for squared units; mixing stoke with centistoke; confusing dynamic and kinematic viscosity units.

Final Answer:

10^-4 m2/s