Ohmmeter principle of operation: Evaluate the statement: “An ohmmeter uses an internal battery to measure the resistance of a resistor.”

Difficulty: Easy

Correct Answer: Correct

Explanation:


Introduction / Context:
Resistance cannot be measured directly without applying a stimulus. Both analog and digital ohmmeters contain an internal source to drive a small current through the device under test, then infer resistance from the measured voltage or current. Recognizing this principle explains common cautions such as “never measure resistance on a live circuit.”


Given Data / Assumptions:

  • Device: ohmmeter function, whether stand-alone or inside a digital multimeter.
  • Unknown resistor is passive and disconnected from external power.
  • Standard two-wire measurement method is used.


Concept / Approach:
An ohmmeter sources a known current I_test (or applies a known voltage V_test) from its internal battery. It then measures the corresponding voltage V_DUT across the resistor or the current through it and computes R using R = V_DUT / I_test or R = V_test / I_DUT. The internal battery is essential for this stimulus. Consequently, if the battery is weak, resistance readings drift or the meter indicates “low battery.”


Step-by-Step Solution:

Recognize measurement method: apply stimulus using internal source.Relate to formula: R = V / I, with one quantity fixed/known by the meter.Understand why live circuits must be avoided: external voltages corrupt readings and may damage the meter.Therefore, the statement about the internal battery is correct.


Verification / Alternative check:
User manuals specify open-circuit test voltages and test currents for various ranges (for example, 0.3 V test on sensitive ranges). This confirms the use of an internal source derived from the meter’s battery.


Why Other Options Are Wrong:

  • Incorrect: Conflicts with the fundamental measurement method.
  • Only true for analog / only above 1 kΩ / depends on lead capacitance: Modern digital multimeters also use internal sources; lead capacitance is irrelevant to static resistance measurement.


Common Pitfalls:
Attempting to measure resistance in-circuit with power applied (backfeeds the meter); measuring components in parallel without isolating them, which lowers the apparent resistance.


Final Answer:
Correct

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion